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3 years ago

What elements are in hay

Chemistry

2 answers:

Ivenika [448]3 years ago

4 0

I looked it up for u

notka56 [123]3 years ago

3 0

I hope that this helps

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Please help

Dmitry [639]

Closest to the nucleus

3 0

3 years ago

A substance that forms a vapor is generally in what physical state at room temperature?liquid or solidsolidliquidgas

Evgesh-ka [11]

The answer is liquid or solid.

That is a substance that forms a vapor is generally in liquid or solid physical state.

The substance that is in liquid or solid physical state, forms vapor.

When heated solid and liquid can be converted into vapor so the answer is solid or liquid is the physical state that forms vapors.

6 0

3 years ago

Perform the following operation and express the answer in scientific notation. 1.26x104 + 2.50x104 [?]x10

ss7ja [257]

Since your multiplying by the same number, 104, both terms, you can group them like this:
104(1.26+2.50)
104(3.76)
391.04

Knowing that scientific notation needs to be a number x, that’s greater or equal to 1, and less then 10.
3.9104 * 10^2

4 0

3 years ago

Volcanoes emit much hydrogen sulfide gas, h2s, which reacts with the oxygen in the air to form water and sulfur dioxide, so2. ev

liq [111]

Answer: There will be 131.3 tons of $SO_{2}$ that will be generated.

Explanation : We have the data as 72 tons of $H_{2}S$ , $O_{2}$ is 101 tons and $H_{2}O$ as 38 tons.

Conversion of 1 ton to kg will be approximately 907.2 Kg

We have to convert the given data of tons into kg for all;

So, moles of $H_{2}S$ = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X $10^{6}$ moles

Now, moles of $O_{2}$ = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X $10^{6}$ moles

And, $H_{2}O$ = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)

= 1.03 X $10^{6}$ moles

Now, we have to calculate the moles of $H_{2}S$

so, 1.916 X $10^{6}$ moles / 2 moles of $H_{2}S$ = 958 X $10^{3}$

Now, for $O_{2}$ ;

So, 2.80 X $10^{6}$ moles / 3 moles of $O_{2}$ = 933.3 X $10^{3}$ moles

Here, we can see that $O_{2}$ is acting as a limiting reactant.

Now, moles of $SO_{2}$ = 2.80 X $10^{6}$ X (2 moles of $SO_{2}$ / 3 moles of $O_{2}$ ) = 1.86 X $10^{6}$

Now converting this into mass,

Mass = Moles X Molar Mass

Mass = 1.86 X $10^{6}$ X (64.066 g/mol X $10^{-3}$ kg/g) X (1 ton / 907.2 Kg)

= 131.3 tons of $SO_{2}$

7 0

3 years ago

Read 2 more answers

Write a c++ program that prints the intial letter of any name

Masteriza [31]

Answer:

please mark as brainliest!!

Explanation:

// C++ program to print initials of a name

#include <bits/stdc++.h>

using namespace std;

void printInitials(const string& name)

{

if (name.length() == 0)

return;

// Since touuper() returns int, we do typecasting

cout << (char)toupper(name[0]);

// Traverse rest of the string and print the

// characters after spaces.

for (int i = 1; i < name.length() - 1; i++)

if (name[i] == ' ')

cout << " " << (char)toupper(name[i + 1]);

}

// Driver code

int main()

{

string name = "prabhat kumar singh";

printInitials(name);

return 0;

}

6 0

3 years ago

Read 2 more answers