What elements are in hay

What greenhouse gas will stay in the atmosphere the longest

Rama09 [41]

Nitrous oxide will stay in the atmosphere the longest.

3 0

4 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb of energy

Ivenika [448]

Answer:

See explanation below

Explanation:

First, you are not providing any data to solve this, so I'm gonna use some that i made up to explain to you, how to solve it. Then, you can go and replace the data you have with the procedure here

The concentration of liquid sodium will be aroun 8.5 MJ of energy, and I will assume that the temperature will not be increased more than 15 °C.

The expression to calculate the amount of energy is:

Q = m * cp * dT

Where:

m: moles needed

cp: specific heat of the substance.

The cp of liquid sodium reported is 30.8 J/ K mole

Replacing all the data in the above formula, and solving for m we have:

m = Q / cp * dT

dT is the increase of temperature. so 15 ° C is the same change for 15 K.

We also need to know that 1 MJ is 1x10^6 J, so replacing all data:

m = 8.5 * 1x10^6 J / 30.8 J/K mole * 15

m = 18,398.27 moles

The molar mass of sodium is 22.95 g/mol so the mass is:

mass = 18,398.27 * 22.95 = 422,240.26 g or simply 422 kg rounded.

7 0

3 years ago

A sample of gas has a mass of 38.8 mg. Its volume is 224 mL at a temperature of 55 °C and a pressure of 886 torr. Find the molar

Pie

Answer:

4g/mol

Explanation:

Firstly, we can get the number of moles of the gas present using the ideal gas equation.

PV = nRT

Here:

P = 886 torr

V = 224ml = 224/1000 = 0.224L

T = 55 degrees celcius= 55+ 273.15 = 328.15K

R = molar gas constant = 62.36 L⋅Torr⋅K−1⋅mol−1

n = PV/RT

n = (886 * 0.224)/(62.36 * 328.15)

n = 0.009698469964 mole

Now to get the molar mass, this is mathematically equal to the mass divided by the number of moles. We have the mass and the number of moles, remaining only the molar mass.

First, we convert the mass to g and that is 38.8/1000 = 0.0388

The molar mass is thus 0.0388/0.009698469964 = 4g/mol

3 0

4 years ago

SYNTHESIS OFCARBONATECTIONLABORATORY SIMULATIONLab Data- X99.00.10CollectedVolume sodium carbonate (mL)Molarity sodium carbonate

evablogger [386]

Answer:

$\begin{gathered} \text{Limiting Reagent = Sodium Carbonate} \\ \text{Percent Yield = 98\%} \end{gathered}$

Explanation:

The chemical reaction talks about the synthesis of calcium carbonate

It is from the reaction between sodium carbonate and calcium chloride

Let us write the equation of reaction as follows:

$Na_2CO_{3(aq)}+CaCl_{2(aq)}\text{ }\rightarrow2NaCl_{(s)\text{ }}+CaCO_{3(aq)}$

Firstly, we want to get the expected mass of calcium carbonate

This speaks about getting the theoretical yield based on the equation of reaction

From the data collected, 90 ml of 0.20 M (mol/L) of sodium carbonate gave calcium carbonate

We need to get the actual number of moles of sodium carbonate that reacted

We can get this by multiplying the volume by the molarity (kindly note that we have to convert the volume to Liters by dividing by 1000)

Thus, we have it as:

$\frac{90}{1000}\times\text{ 0.1 = 0.009 moles}$

Hence, we see that 0.009 moles of sodium carbonate reacted theoretically

Since 1 mole of sodium carbonate gave 1 mole calcium carbonate, it is expected that 0.009 mole of sodium carbonate will give 0.009mole of calcium carbonate

What we have to do now is to get the theoretical grams of calcium carbonate produced

That would be the product of the number of moles of calcium carbonate and its molar mass

The molar mass of calcium carbonate is 100 g/mol

The theoretical yield (expected mass) is thus:

$100\text{ g/ mol }\times\text{ 0.009mol = 0.9 g}$

Finally, we proceed to get the percentage yield which is calculated using the formula below:

$\text{Percent Yield = }\frac{Actual\text{ yield}}{\text{Theoretical yield}}\times\text{ 100 \%}$

The actual yield is the observed mass which is given as 0.88 g

The percent yield is thus:

$\frac{0.88}{0.9}\times\text{ 100 = }98\text{ \%}$

7 0

1 year ago

Lab activity - Law of Conservation of Mass with vinegar and baking soda.

lesya [120]

Answer: I BIG DUMB

Explanation:

7 0

3 years ago