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vlabodo [156]
3 years ago
10

Can someone please please help me with the first two !!!! I really need to turn this in !!!!!

Chemistry
1 answer:
kati45 [8]3 years ago
7 0

Answer:

Be Electron configuration: 1s2 2s2

Be Orbital Diagram: \//\    \//\ (it would be little arrows going up and down to show the spins)

F Electron Configuration: 1s2 2s2 2p5

F Orbital Diagram: \//\    \//\    \//\ \//\ \/

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A sample of a gaseous substance at 25 celcius and 0.862 atm has a density of 2.26 g/l. what is the molecular weight
faust18 [17]
Molecular weight = 2 * vapour density  at STP.
5 0
3 years ago
Who is good at chemistry?! HMU asap!!!​
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Id say i’m good i guess. send links for the brainly problems u need help with!
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3 years ago
How many grams of oxygen gas are required to produce 65.75 grams of steam?
Nana76 [90]

Answer:

The mass of oxygen gas required to produce 65.75 grams of steam is approximately 162.2 grams

Explanation:

From the question, we have the following chemical reaction equation;

2C₃H₁₈(l) + 25O₂ (g) → 16CO₂(g) + 18H₂O (g)

The molar mass of oxygen, O₂ = 32 g/mol

The molar mass of steam, H₂O = 18.01528 g/mol

25 moles of oxygen are required to produce 18 moles of steam

Therefore, according to  Proust's law of definite proportions;

(32 × 25) g of oxygen are required to produce (18 × 18.01528) g of steam

65.75 g of steam will be produced by (32 × 25)/(18 × 18.01528) × 65.75 g ≈ 162.2 g of oxygen O₂.

3 0
3 years ago
Since vinegar is 5% acetic acid and 95% water, find the mole ratio of acetic acid to water in 100 g of vinegar? Hint: Instead of
Oksanka [162]

The mole ratio of acetic acid to water in 100 g of vinegar is 0.015 : 0.985.

<h3>What is the mole ratio of acetic acid to water in 100 g of vinegar?</h3>

The mole ratio of acetic acid to water in 100 g of vinegar is determined from their percentage composition.

The percentage composition of acetic acid and water in vinegar is 5% acetic acid and 95% water.

In 100 g of vinegar, there are 5 g of acetic acid and 5 g of water.

Moles = mass/molar mass

molar mass of acetic acid = 62 g/mol

molar mass of water = 18 g/mol

moles of vinegar = 5/62 = 0.08

moles of water = 95/18 = 5.28

total moles = 5.36

Mole ratio of vinegar to water = 0.08/5.36 : 5.28/5.36

Mole ratio of vinegar to water = 0.015 : 0.985

In conclusion, the mole ratio is determined from the percentage composition of acetic acid and water in vinegar.

Learn more about mole ratio at: brainly.com/question/19099163

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7 0
2 years ago
How can toxicant absorption be reduced after exposure to the skin? How can absorption be reduced for orally consumed chemicals?
zmey [24]

Answer:

The toxicant absorbtion can be reduced after exposure to the skin the surrounding clothing shoes or gloves should be removed or torn off than the part of the body which was exposured to the toxicant should be immediatly washed using clean running water for a while, with cold shower being the most recommended splashing method. In case of absorption for orally consumed chemicals should check on any remaining toxicant residue and be removed from the mouth. Vomiting should be induced to patients that are still conscious by providing them with liquids that can provoke vomiting. This will help in removing the toxicant in the intestinal and reduce their effect. Gastric lavage should then be done to induce diarrhea.  

Explanation:

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3 years ago
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