Explanation:
1.
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils whereas erosion is the movement of weathered materials from one area to the other.
Erosion moves weathered materials and it causes them to change position. For example loose chips of rocks broken down as the rock weakens through alternate wetting and drying in tropical regions will remain in-situ until the agents of erosion comes to carry them away. The breaking is weathering and the carrying is erosion.
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2.
Examples of mechanical weathering:
- Frost action
- Pressure release
Examples of chemical weathering:
There are two types of weathering:
- In mechanical weathering, a rock disintegrates into smaller chunks by the action of wind, water and glacier. For example in temperate and polar regions, water within rocks freezes. When water freezes it expands and causes tension within the rock. When temperature drops, water melts and the tension is relieved. This process causes a rock to crack. The crack will eventually become wider with time.
- In chemical weathering, a rock decomposes by the action of chemicals formed in the rock. In karst regions where limestone forms, combination of rain water and carbon dioxide forms weak carbonic acid that reacts with calcite in limestone.
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Atomic number
atomic mass
group|family
periods
and element symbols
Answer:
V₂ = 530.5 mL
Explanation:
Given data:
Initial temperature = 20.0°C
Final temperature = 40.0 °C
Final volume = 585 mL
Initial volume = ?
Solution:
Initial temperature = 20.0°C (20+273 = 293 K)
Final temperature = 40.0 °C (40+273 = 323 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₁ = V₂T₁ /T₂
V₂ = 585 mL × 293 K / 323 K
V₂ = 171405 mL.K / 323 K
V₂ = 530.5 mL
The decomposition reaction for hydrogen peroxide is given below:
2
→ 2 O +
This is a decomposition reaction.
Reactions in which a reactant breaks into two or more products are known as Decomposition reactions.
AB → A + B
here, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction
The decomposition reaction of decomposing hydrogen peroxide is exothermic. When the hydrogen peroxide undergoes a decomposition reaction, heat is also released along with water and oxygen.
Hence the reaction for decomposing hydrogen peroxide is :
2 → 2 O +
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