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Sergeeva-Olga [200]
3 years ago
8

Question

Chemistry
1 answer:
Shalnov [3]3 years ago
8 0
The Kelvin Scale is used, so the answer is temperature :)
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When 50.0 ml of a 0.3000 m agno3 solution is added to 50.0 ml of a solution of mgcl2, an agcl precipitate forms immediately. the
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<span>0.0165 m The balanced equation for the reaction is AgNO3 + MgCl2 ==> AgCl + Mg(NO3)2 So it's obvious that for each Mg ion, you'll get 1 AgCl molecule as a product. Now calculate the molar mass of AgCl, starting with looking up the atomic weights. Atomic weight silver = 107.8682 Atomic weight chlorine = 35.453 Molar mass AgCl = 107.8682 + 35.453 = 143.3212 g/mol Now how many moles were produced? 0.1183 g / 143.3212 g/mol = 0.000825419 mol So we had 0.000825419 moles of MgCl2 in the sample of 50.0 ml. Since concentration is defined as moles per liter, do the division. 0.000825419 / 0.0500 = 0.016508374 mol/L = 0.016508374 m Rounding to 3 significant figures gives 0.0165 m</span>
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Assuming 80 mg of vitamin c present 29.57 ml if oj how many milliliters of 0
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For all of the following questions 20.00 mL of 0.200 M HBr is titrated with 0.200 M KOH.
HACTEHA [7]

Answer :

The concentration of H^+ before any titrant added to our starting material is 0.200 M.

The pH based on this H^+ ion concentration is 0.698

Explanation :

First we have to calculate the concentration of H^+ before any titrant is added to our starting material.

As we are given:

Concentration of HBr = 0.200 M

As we know that the HBr is a strong acid that dissociates complete to give hydrogen ion H^+ and bromide ion Br^-.

As, 1 M of HBr dissociates to give 1 M of H^+

So, 0.200 M of HBr dissociates to give 0.200 M of H^+

Thus, the concentration of H^+ before any titrant added to our starting material is 0.200 M.

Now we have to calculate the pH based on this H^+ ion concentration.

pH : It is defined as the negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

pH=-\log (0.200)

pH=0.698

Thus, the pH based on this H^+ ion concentration is 0.698

3 0
3 years ago
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