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3 years ago

Question

Chemistry

1 answer:

Shalnov [3]3 years ago

8 0

The Kelvin Scale is used, so the answer is temperature :)

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4 multicellular yes autotrophic It is unable to move around its environment. A. Kingdom animalia B. kingdom fungi C. kingdom pla

Alina [70]

Hello there.

4 multicellular yes autotrophic It is unable to move around its environment.

D. kingdom protista

5 0

2 years ago

43 mg = [?]g A. 0.043 g B. 4.3 g C. 4300 g D. 43,000 g

Ymorist [56]

Answer:

Option A (0.043 g) is the correct answer.

Explanation:

Given:

= 43 mg

As we know,

$1 \ mg = \frac{1}{1000} \ g$

then,

⇒ $43 \ mg = \frac{43}{1000} \ g$

$= 0.043 \ g$

Thus, the above is the correct alternative.

4 0

3 years ago

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago

Can someone please help me with this it's for a grade.

alukav5142 [94]

Answer:

The Answer is 'D'

Explanation:

The diagram on the down side shows the behavior of the particles of a liquid so I suppose it is the ocean. While the top diagram shows the behavior of the particles of a gas so I am sure it's the air. Therefore I chose the last diagram because it describes exactly how you wanted in the question, which is the Ocean's water evaporating to become gas or the 'air' as we say

Thank you and I hope you like this answer!

7 0

3 years ago

Can someone please please help me out ?

GarryVolchara [31]

Answer:

4.823 x 10^-19 J

Explanation:

Energy is calculated by E = hv where h - Planck's constant in joule.s

v - frequency.

in this particular question the wave length is 4.12 x 10^-7 m. to exhaustively use this we need a relation between wave length & frequency. c=wv where C is approximately 3 x 10^8m/s

-v = c/w = 3x10^8m/s / 4.12 x 10^-7m = 7.28 x 10^14 Hz or 1/sec

now we can simply use Planck's constant in E=hv =

(6.626 x 10^-34) x (7.28 x 10^14Hz) = 4.823 x 10^-19 J.

6 0

2 years ago