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3 years ago

5

WILL MARK BRAINIEST IF CORRECT.

1 answer:

bonufazy [111]3 years ago

3 0

Answer:

1, 2, 5 and 6 are the answers.

Step-by-step explanation:

2 is correct because the arrow shows that the number line continues till infinity. 5 is correct because any fraction is possible as no restriction of integer value is placed. Any number less than 7 is not included. There are some confusions with 1 as it's not a solid color, So, I assume -7 is not included.

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What is the multiplicative inverse of -27 and what is the multiplicative inverse for 7/9 and -9/16

liberstina [14]

The multiplicative inverse of a number is the number when you multiply it, it gives you the product of 1.

So for - 27, what number will give us 1 when we multiply it by -27

-27 * -1/27 = 1

So the multiplicative inverse of -27 = -1/27

7/9 * 9/7 = 1

-9/16 * -16/9 = 1

So in essence, just take the number and flip it

-27 = -1 / 27

7/9 = 9/7

-9/16 = -16/9

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3 years ago

A boat is heading towards a lighthouse,

larisa86 [58]

Answer: 920.3 ft

Step-by-step explanation:

$\tan 7^{\circ}=\frac{113}{x} \\ \\ x(\tan 7^{\circ})=113 \\ \\ x=\frac{113}{\tan 7^{\circ}} \approx \boxed{920.3 \text{ ft}}$

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1 year ago

Instructions: Find the measure of the indicated angle

Tanya [424]

Answer:

46 degree

I hope this will help you

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3 years ago

5% times blank equals 2.5<br><br> NEED ASAP

lapo4ka [179]

Answer:

0.5

Step-by-step explanation:

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3 years ago

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If the sides of two similar triangles are in the ratio of 3:5, find the ratio of their areas.

Kazeer [188]

Ratio of areas of similar triangles is 9 : 25.

Solution:

Given data:

Ratio of sides of two similar triangles = 3 : 5

To find the ratio of areas of the triangles:

We know that,

<em>In two triangles are similar, then the ratio of their area is equal to the square of the ratio of their sides.</em>

$$\text{Ratio of areas} = \frac{\text{Area of triangle 1}}{\text{Area of triangle 2} }$

$$=\left(\frac{3}{5}\right) ^2$

$$=\frac{9}{25}$

Ratio of areas of similar triangles is 9 : 25.

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3 years ago

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