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adelina 88 [10]
3 years ago
13

Which phrase describes a planet’s period of rotation? A. the shape of its orbit B. its tilt relative to the sun C. one complete

spin on its axis D. one complete orbit around the sun
AND TELL WHY
Physics
2 answers:
SashulF [63]3 years ago
8 0
C. one complete spin on its axis because the rotation is referring to the planet's period of rotation. D is called a revolution. B determines the seasons on the planets. A is called an ellipse.
Sergeeva-Olga [200]3 years ago
3 0

Answer:

C. one complete spin on its axis            

Explanation:

A planet rotates about its axis as well as revolves around the star which is at the center of the star system, of which the planet is part of. In solar system, the 8 planets revolve around the Sun.

Period of rotation refers to the one complete spin of the planet about its axis. Period of revolution refers to the one complete orbit around the Sun.

For example, the Earth rotates about its axis in 24 hours where as it revolves around the Sun in 365 days.

You might be interested in
What causes the very high surface temperature on Venus
IRINA_888 [86]
Venus is so hot because it is surrounded by a very thick atmosphere which is about 100 times more massive than our atmosphere here on Earth. As sunlight passes through the atmosphere, it heats up the surface of Venus. ... The heat becomes trapped and builds up to extremely high temperatures.
8 0
3 years ago
A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

  • Mass of the first puck = m_1\ =\ 5\ kg
  • Mass of the second puck = m_2\ =\ 3\ kg
  • initial velocity of the first puck = u_1\ =\ 3\ m/s.
  • Initial velocity of the second puck = u_2\ =\ -1.5\ m/s.

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = v_2\ =\ 2.31\ m/s.

Let v_1 be the final velocity of first puck after the collision.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = 25\times 10^{-3}\ sec

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0
3 years ago
A massless, rigid board is placed across two bathroom scales that are separated by a distance of 1.71 m. A person lies on the bo
Nata [24]

Answer:

Let the weight of the person be W and be located at a distance 'a' from the left scale as shown in the figure

Since the body is in equilibrium we can use equations of statics to analyse the problem.

Taking Sum of Moments about A we have

316\times 1.71-W\times a=0\\\\

Taking Sum of Moments about B we have

475\times 1.71-W\times (1.71-a)=0\\\\

Solving the above 2 equations for W and 'a' we get

316\times 1.71=W\times a\\\\475\times 1.71-W\times 1.71=-Wa\\\\\therefore W=\frac{316+475}{1}=791N\\\\\therefore a=\frac{316\times 1.71}{791}=0.683m

8 0
3 years ago
A car has a mass of 1,000 kilograms. The weight of the car is
ahrayia [7]

Answer : The weight of the car is 9800 N

Explanation :

It is given that,

The mass of the car, m = 1000 kg

We have to find the weight of the car. The weight of an object is defined as the force acting on it under the action of gravity. The mass of an object is the amount of matter present in it.

Using second law of motion :

W = m g

Where

m is the mass of the car

g is the acceleration due to gravity g = 9.8 N/kg

W = 1000 kg × 9.8 N/kg

W = 9800 N

So, the weight of the car is 9800 N.

Hence, this is the required solution.

6 0
3 years ago
Find the current flowing across the 20 ohm resistor.​
Aliun [14]

Answer:

15 is it

Explanation:

6 0
3 years ago
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