1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NNADVOKAT [17]
3 years ago
11

A 25 kg child runs at a speed of 5.0 m/s and jumps onto a stationary shopping cart and holds on for dear life. The cart has mass

12 kg. Assuming the child rides on the cart after the collision, find the speed of the child and shopping cart just after the child jumps on. show all work please
Physics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

3.38 m/s

Explanation:

Mass of child = m₁ = 25

Initial speed of child = u₁ = 5 m/s

Initial speed of cart = u₂ = 0 m/s

Mass of cart = m₂ = 12 kg

Velocity of cart with child on top = v

This is a case of perfectly inelastic collision

m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\frac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\frac{25\times 5+12\times 0}{25+12}\\\Rightarrow v=\frac{125}{37}\\\Rightarrow v=3.38\ m/s

Velocity of cart with child on top is 3.38 m/s

You might be interested in
Consider a hot air balloon rising vertically from a launch site located on the ground. A person is initially standing 10 m from
abruzzese [7]

Answer:

The distance between the person and the balloon after 2 seconds the person starts walking is changing on 4.47 m/s

Explanation:

The relative position between the balloon and the person is found using Galileo's relativity principle:

\overrightarrow{r_{b/p}}=\overrightarrow{r_{b}}+\overrightarrow{r_{p}} (1)

with Rb the position of the balloon and Rp the position of the person respect with the origin (See Figure 1). Because we don’t have those positions but we know the constant velocities, we can relate the positions (R) with the velocities (v) with the kinematic equation:

\overrightarrow{R}=\overrightarrow{v}*t (2)

So equation (1) is:

\overrightarrow{R_{b/p}}=\overrightarrow{v_{b}*t}+\overrightarrow{R_{p}}=(v_{b}*t)\,\hat{j}-R_{p\,}\hat{i} (3)

with \hat{j} and \hat{i} the unitary vectors on y and x direction respectively.

We see from our initial condition (See figure 2) that:

R_{p}=(10-v_{p}*t) (4)

So if we put this on (3) and divide by time we have:

\frac{\overrightarrow{R_{b/p}}}{t}=\overrightarrow{v_{b/p}}=\frac{(v_{b}*\cancel{t})}{\cancel{t}}\,\hat{j}-\frac{(10-v_{p}*t)}{t}\hat{i}(5)

But we are interested in how fast a distance is changing, and that is a speed so:

v_{b/p}=\sqrt{v_{b}^{2}+\left(\frac{(10-(v_{p}*t))}{t}\right)^{2}}=\sqrt{4^{2}+\left(\frac{(10-(3*2))}{2}\right)^{2}}\simeq4.47\,\frac{m}{s}

3 0
3 years ago
A pirate ship shoots a cannon towards an oncoming ship. The cannon ball has a mass of 25 kg and the ship has a mass of 2500 kg.
mars1129 [50]

Answer:

25 m/s in the opposite direction with the ship recoil velocity.

Explanation:

Assume the ship recoil velocity and velocity of the cannon ball aligns. By the law of momentum conservation, the momentum is conserved before and after the shooting. Before the shooting, the total momentum is 0 due to system is at rest. Therefore, the total momentum after the shooting must also be 0:

m_sv_s + m_bv_b = 0

where m_s = 2500 kg, m_b = 25 kg are masses of the ship and ball respectively. v_s = 0.25 m/s, v_b are the velocities of the ship and ball respectively, after the shooting.

2500*0.25 + 25*v_b = 0

25v_b = -2500*0.25

v_b = -2500*0.25/25 = -25 m/s

So the cannon ball has a velocity of 25 m/s in the opposite direction with the ship recoil velocity.

3 0
3 years ago
A net force of 3 N accelerates a mass of 3 kg at the rate of 1 m/s2. The acceleration of a mass of
Cloud [144]

Answer:

,mkjh ,bkl m,

Explanation:

3 0
4 years ago
When you pedal a bicycle, maximum torque is produced when the pedal sprocket arms are in the horizontal position, and no torque
poizon [28]

Answer:

This is because when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.  

Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.

Explanation:

τ = r×F×sinθ

where;

τ is the torque produced

r is the radius of the pedal sprocket arms

F is the applied force

θ is the angle between the applied force and the pedal sprocket arms

Maximum torque depends on the value of θ,

when the pedal sprocket arms are in the horizontal position, it is perpendicular to the applied force, and the angle between the applied force and the pedal sprocket arms is 90⁰.

τ = r×F×sin90⁰ = τ = r×F(1) = Fr (maximum value of torque)

Also, when the pedal sprocket arms are in the vertical position, it is parallel to the applied force, and the angle between the applied force and the pedal sprocket arms is 0⁰.

τ = r×F×sin0⁰ = τ = r×F(0) = 0 (torque is zero).

4 0
4 years ago
List the forms of renewable energy that are curently in use
aliya0001 [1]

Here are the ones that I know about
and can think of just now:

-- wind
-- solar
-- nuclear
-- tidal
-- hydro
-- geothermal
-- biomass

4 0
3 years ago
Other questions:
  • Garret's swimming coach is giving him important and helpful tips to improve his swimming skills. Which gesture suggests that Gar
    11·2 answers
  • You start driving north for 9 miles, turn right , and drive East for another 40 miles. At the end of driving, what is your staig
    6·1 answer
  • Calculate the power a car engine contributes to speeding the 1400 kg car up to a highway speed of 60.0 mi/h in 14.0 s.
    10·2 answers
  • How would you find the average speed of a cyclist throughout an entire race
    6·1 answer
  • Match the technology that uses radio waves to the field in which it is used
    13·1 answer
  • A bat locates insects by emitting 25.3 kHz ultrasonic chirps and then listening for echoes from insects flying around it. Humans
    6·1 answer
  • What is Minimum Threshold Frequency?​
    7·2 answers
  • A larger car takes more force to move._
    8·1 answer
  • Whatb19 ÷117= some help me with this
    11·1 answer
  • A 80.4-kg halfback moving south with a speed of 4.91 m/s is hit by a 96.9-kg opponent moving north with a speed of 2.89 m/s. If
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!