Given from the problem :mass m = 413 kg;coefficient of friction u = 0.0163;acceleration due to gravity g = 9.8 m/s2;inclined angle @1 = 14.3;inclined angle @2 = 4.69;distance travelled d = 175 m;applied fore F = 410 N; the component of the force from the donkey in the direction of motion isF2 = F1
[email protected]= 397.2964498768165 N
Fy = N - mg
[email protected] = 0N = mg
[email protected] = 4037.964151113007 NFx = F2 - mg
[email protected] - f = mahere f = u N=65.8188156631420141
F2 - mg
[email protected] - f = maa = F2 - mg
[email protected] - f/ m=0.31923412183075155 m/s^2
work done by donkeyW = F2 d=69526.8787284428875 J
9514 1404 393
Answer:
- moderate low: 82
- moderate high: 112.75
- vigorous low: 123
- vigorous high: 174.25
Explanation:
When calculations are repetitive, I find it convenient to use a calculator that can work with tables.
The PMHR is (220 -15) = 205.
Each of the other heart rates is computed as the formula shows. For example, the low moderate heart rate is 205×0.40 = <u> 82 </u> bpm
The other rates are shown in the attached table. They are computed the same way.
Answer: B) Solid water to liquid water.
Explanation: This would be the melting of water or a transition of solid water to liquid water as energy is added.
Answer:
20.7 billion = 20.7E9 converting to units of 10
20.7E9 km = 20.7E12 m
t = S /v = 20.7E12 m / 3.0E8 m/s = 6.9E4 s = 69000 s
69000 s = 1150 min = 19.2 hrs
