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andreyandreev [35.5K]
3 years ago
10

A car starts from the rest and retains the acceleration of 4m/S2 in 20 second.calculate its final velocity​

Physics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

80m/s

Explanation:

v=u +at

but the car start from rest so intial velocity (u) =o

therefore,

v=0+4(20)

v=80m/s

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An ideal gas is enclosed in a cylinder that has a movable piston on top. The piston has a mass m and an area A and is free to sl
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Answer:

Explanation:

Given mass of piston \left ( m\right )

no. of moles =n

Given Pressure remains same

Temperature changes from T_1 to T_2

Work done\left ( W\right ) is given by=\int_{V_1}^{V_2}PdV

W=P\left ( V_2-V_1\right )

also PV_1=nRT_1

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W=nR\left ( T_2-T_1\right )

4 0
3 years ago
Which part of the brain serves to regulate the endocrine system?
Debora [2.8K]

Answer:

hypothalamus

Explanation:

The hypothalamus is known as the master switchboard because it's the part of the brain that controls the endocrine system. The pituitary gland, which hangs by a thin stalk from the hypothalamus, is called the master gland of the body because it regulates the activity of the endocrine glands.

7 0
3 years ago
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A greyhound's velocity changes from 10 meters per second to 15 meters per second in 0.5 second. What is the greyhound's average
alexgriva [62]
I think it is 5 m/s  
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3 years ago
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A boat is able to move through still water at 20 m/s. It makes a round trip to a town 3.0 km upstream. If the river flows at 5m/
Salsk061 [2.6K]

Answer:

Option e) 320 s

Explanation:

Here, distance = 3.0 km = 3000 m

The velocity of boat when it is going upstream;

Upstream velocity = velocity of boat in still water - velocity of river flow

So, Upstream velocity =20m/s-5m/s=15m/s

So,Time to go upstream

(t_{1}) =\frac{Distance}{Velocity}=\frac{3000m}{15m/s} =200 s

The velocity of boat when it is going downstream;

Downstream velocity = velocity of boat in still water + velocity of river flow

So, Downstream velocity =20m/s+5m/s=25m/s

So,Time to go downstream

(t_{2}) =\frac{Distance}{Velocity}=\frac{3000m}{25m/s} =120 s

So, total time (t) = t_{1}+t_{2}=200s+120 s=320s

Option E is the correct answer.

3 0
3 years ago
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-g A small block is attached to an ideal spring and is moving in SHM on a horizontal frictionless surface. The amplitude of the
Nina [5.8K]

Answer:

a= 92. 13 m/s²

Explanation:

Given that

Amplitude ,A= 0.165 m

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We know that maximum velocity in the SHM  given as

V(max)  = ω A

ω=Angular speed

A=Amplitude

\omega =\dfrac{3.9}{0.165}\ rad/s

ω=23.63 rad/s

The maximum acceleration given as

a = ω² A

a= (23.63)² x 0.165 m/s²

a= 92. 13 m/s²

Therefore the maximum magnitude of the acceleration will be 92. 13 m/s².

5 0
3 years ago
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