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andreyandreev [35.5K]
3 years ago
10

A car starts from the rest and retains the acceleration of 4m/S2 in 20 second.calculate its final velocity​

Physics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

80m/s

Explanation:

v=u +at

but the car start from rest so intial velocity (u) =o

therefore,

v=0+4(20)

v=80m/s

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Tire inflation is very important to the safe and economical operation of any vehicle. Technician A says that the tire pressure s
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Answer:

Both technicians A and B are correct, the information on how to fill the car tires can be located on the tire and on the placard on the driver's door jam

Explanation:

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A centrifugal pump discharges 300 gpm against a head of 55 ft when the speed is 1500 rpm. The diameter of the impeller is 15.5 i
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Answer: Question 1: Efficiency is 0.6944

Question 2: speed of similar pump is 2067rpm

Explanation:

Question 1:

Flow rate of pump 1 (Q1) = 300gpm

Flow rate of pump 2 (Q2) = 400gpm

Head of pump (H)= 55ft

Speed of pump1 (v1)= 1500rpm

Speed of pump2(v2) = ?

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Diameter of impeller in pump 2= 15in = 0.381

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Assuming cold water, S.G = 1.0

eff= (H x Q x S.G)/ 3960 x B.H.P

= (55x 300x 1)/3960x 6

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Question 2:

Q = A x V. (1)

A1 x v1 = A2 x V2. (2)

Since A1 = A2 = A ( since they are geometrically similar

A = Q1/V1 = Q2/V2. (3)

V1(m/s) = r x 2π x N(rpm)/60

= (0.3937x 2 x π x 1500)/2x 60

= 30.925m/s

Using equation (3)

V2 = (400 x 30.925)/300

= 41.2335m/s

To rpm:

N(rpm) = (60 x V(m/s))/2 x π x r

= (60 x 41.2335)/ 2× π × 0.1905

= 2067rpm.

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3 years ago
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