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blagie [28]
3 years ago
15

The acceleration due to gravity on Earth is 9.81 m/s² [down]. A hockey puck was launched from the ice with a velocity of 26.9 m/

s [up]. Assuming no friction, determine the velocity of the hockey puck when it hits the ice.
Physics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

A hockey puck having a mass of 0.30 kg slides on the frictionless, horizontal surface of an ... magnitude of 5.0 N, and the force F2 has a magnitude of 8.0 N. Determine both ... A large man and a small boy stand facing each other on frictionless ice. They ... A hockey puck on a frozen pond is given an initial speed of 20.0 m/s.

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A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling
ivann1987 [24]

Answer:

42.99°

Explanation:

F_h = Kinetic friction force

F_{\theta} = Pulling force at angle \theta

N_h = Weight of the box = 150 N

Kinetic friction force

F_h=\muN_h

Pulling force at angle \theta

F_{\theta}=\muN_{\theta}

N = Pulling force

According to question

\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N

Applying Newton's second law in the vertical direction we get

N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}

The angle is 42.99°

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