Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
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Hope this helps!! All credit goes to Google though
Answer:
The value is 
Explanation:
From the question we are told that
The diameter of each wheel is 
The mass of the motorcycle is 
The rotational kinetic inertia is 
The mass of the rider is 
The velocity is 
Generally the radius of the wheel is mathematically represented as
=> 
=> 
Generally from the law of energy conservation
Potential energy attained by system(motorcycle and rider ) = Kinetic energy of the system + rotational kinetic energy of both wheels of the motorcycle
=> 
=> 
Here 
is the angular velocity which is mathematically represented as
So
Here 
![395 * 9.8 * h = 0.5 * 395 * (23.61)^2 + 2.1 *[\frac{ 23.61}{ 0.26} ] ^2](https://tex.z-dn.net/?f=395%20%2A%20%209.8%20%2A%20%20h%20%20%3D%20%20%200.5%20%20%20%20%2A%20%20%20395%20%2A%20%20%2823.61%29%5E2%20%2B%20%202.1%20%20%2A%5B%5Cfrac%7B%2023.61%7D%7B%200.26%7D%20%5D%20%5E2)
=>
Answer:
y = 2.196 m
Explanation:
Mass, m = 76 kg
distance from axis of rotation, x = 0.38 m
Second Force, F = 129 N
moment arm of the second force, y = ?
Now, equating moments for the equilibrium
So,
m g × x = F x y
76 x 0.38 x 9.81 = 129 x y
y = 2.196 m
Hence, the length of the moment arm is equal to 2.196 m.
