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Talja [164]
3 years ago
16

What is the number “4” in SiCl4? a subscript a coefficient a product a reactant

Physics
2 answers:
Bad White [126]3 years ago
6 0
It is a) a subscript
Svetlanka [38]3 years ago
4 0

Answer: 4 is the subscript in SiCl_{4}.

Explanation:

We know that,

Subscript: The number of atom present in a given compound.

In SiCl_{4}, 4 represents the number of chlorine atom in 1 mole of Silicon tetra chloride.

Coefficient: Number of atom which is used in reaction.

For example: In 3SiCl_{4}, 3 is the coefficient of silicon tetra chloride.

A Product : In the balance equation, right hand side is called product.

A reactant : In the balance equation, left hand side is called reactant.

For example: the balance equation is

2Mg+O_{2}\rightarrow 2MgO

In this equation, 2Mg+O_{2} is the reactants and 2MgO is products.

Hence, 4 is the subscript in SiCl_{4}.

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Assoli18 [71]

Answer:

The net force is zero, so the acceleration is zero

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force applied to it, according to the equation:

\sum F = ma (1)

where

\sum F is the net force on the object

m is the mass of the object

a is its acceleration

In this problem, we have a sled acted upon two forces, F_1, F_2. So the net force on the sled is

\sum F = F_1 + F_2 (2)

however, we are told that the two forces are equal in magnitude but in opposite directions, so

F_1 = F\\F_2 = -F

So, eq.(2) becomes

\sum F = F+(-F) = 0

and so eq.(1) becomes

\sum F = ma = 0

which means

a=0

so the acceleration of the sled is zero, and if the sled was at rest, it will not move.

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3 years ago
One half of a balanced chemical equation is shown. 3Mg(OH)2 + 2H3PO4
balandron [24]
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4 0
2 years ago
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adelina 88 [10]
Application and weight?!
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3 years ago
Suppose two objects are attracting each other gravitationally. If you double the distance between them, the strength of their gr
Roman55 [17]

Answer:

decreases by a factor of 4

Explanation:

Lets take mass of the objects are m₁ and m₂ and the distance between them at initial condition is R.

We know that attraction force between two object given as

F=G\dfrac{m_1m_2}{R^2}

G=Constant

If distance become 2 R

R' = 2R

F'=G\dfrac{m_1m_2}{R'^2}

F'=G\dfrac{m_1m_2}{(2R)^2}

F'=G\dfrac{m_1m_2}{4R^2}

F'=\dfrac{1}{4}\times G\dfrac{m_1m_2}{R^2}

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3 0
3 years ago
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