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Vadim26 [7]
2 years ago
14

Non-electrolyte = A, 10.6 grams, dissolved in solvent B, 740 grams, the boiling point of the solution is higher than the boiling

point of the solvent
Pure dissolved in 0.284 ° C. Determine the Kb value of solvent B. Set the molecular weight of A = 106.
Chemistry
1 answer:
Thepotemich [5.8K]2 years ago
8 0

Answer:

2.1 °C/m

Explanation:

Hello, for this exercise, consider the formula:

T_{solution}-T{solvent}=K_bm_solute

Considering that the difference in the temperature is 0.284°C, and the given molality by:

m_{solute}=\frac{10.6g\frac{1mol}{106g}}{740g*\frac{1kg}{1000g} } \\m_{solute}=0.135m

Now, solving for K_b, we get:

K_b=\frac{0.284C}{0.135m}\\K_b=2.1 C/m

Best regards.

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A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t
FrozenT [24]

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

4 0
2 years ago
a mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed
Dafna11 [192]

A mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.

<h3>What is concentric hydrochloric acid?</h3>

The concentric hydrochloric acid is used for the analysis of organic and inorganic mixture like  lithium chloride, lithium carbonate, and lithium nitrate it releases fumes and cannot be touched with normal hands.

Always use a dropper to use it and for the chemical analysis.

Therefore, mixture consisting of only of lithium chloride, lithium carbonate, and lithium nitrate was analyzed by the help of concentric hydrochloric acid.

Learn more about concentric hydrochloric acid, here,

brainly.com/question/24586675

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6 0
1 year ago
Give an example of a specialized cell.
Gre4nikov [31]

Answer:

Muscle cell

Explanation:

An example of a specialized cell would be a muscle cell, which allows muscles to contract. A specialized cell has a specific function.

4 0
2 years ago
Read 2 more answers
Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of
lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

U_{2}-U_{1}=Q-W

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

dw=Pdv

The pressure is constant, so:  w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg} (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

U_{2}-U_{1}=500-(3*75)=275kJ

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

P_{1}V_{1}=nRT_{1}

P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}  

Subtracting the first from the second:

1.5P_{1}V_{1}=nR(T_{2}-T_{1})

Isolating T_{2}:

T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}

Assuming that it is water steam, n=0.1666 kmol

V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}

T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76 ºC

7 0
3 years ago
How many grams of NaOH are needed to make 500 mL of a 2.5 M NaOH solution
Veronika [31]
The number of grams  of NaOH  that are needed to make 500 ml of 2.5 M NaOH solution

calculate the number of moles =molarity x volume/1000

= 2.5 x 500/1000 = 1.25 moles

mass = moles  x molar mass of NaOH

= 1.25 x40= 50 grams of NaOH
4 0
3 years ago
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