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frutty [35]
1 year ago
10

Write an equation that gives the relationship between the cross-sectional area (a), the volume (v), and the thickness of a cylin

der.
Chemistry
1 answer:
Mazyrski [523]1 year ago
7 0
V = at
Where t is thickness
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A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi
Naddika [18.5K]
Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>molality =n(solute) / m(solvent) =\ \textgreater \  4.8m = 4.8mole / 1kg
= 4.8 mole * 98 g/mole = 470g
m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \=\ \textgreater \  Molarity = 4.8 mole / 1.2 L = 4 M m(H2SO4)  which is =<span>470g

</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
Molarity = n(solute) / V(solution) =\ \textgreater \
5 0
2 years ago
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia. How much precipitate would be produced? Describe the amount of
barxatty [35]

The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.

<h3>What is precipitate?</h3>

Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.

Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is

2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄

The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.

Learn more about precipitate.

brainly.com/question/18109776

#SPJ1

4 0
1 year ago
Metamorphic rocks that melt in a holt fluid can recystallize into a different form of rock
kotykmax [81]
I think that type of rock is call Igneous rock because the igneous rock is molten rock from volcanoes. 
7 0
2 years ago
Does it make a difference if the jar is square or round? What about the size of the jar or glass?
morpeh [17]

no it doesn't make differance at all ...only the material used make difference

4 0
3 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6
joja [24]

<u>Answer:</u> The concentration of CH_3COOH comes out to be 0.16 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL

Putting values in above equation, we get:

1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M

Hence, the concentration of CH_3COOH comes out to be 0.1862 M.

4 0
2 years ago
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