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igor_vitrenko [27]
2 years ago
8

Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C & occupying 2.53 L. You mu

st show all of your work to earn credit. **Don't forget to convert your Celsius temperature to Kelvin**
*picture attached !!*

Chemistry
1 answer:
chubhunter [2.5K]2 years ago
4 0

Answer:

The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

    = 334

2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

P = 2.32 atm

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How much heat (kJ) is absorbed by 229.1 g of water in order for the temperature to increase from 25.00∘C to 32.50∘C?
hammer [34]

Answer:

(Q1) 9.42 kJ.

(Q2) 1.999 kJ

Explanation:

Heat: This is a form of Energy that brings about the sensation of warmth.

The S.I unit of Heat is Joules (J).

The heat of a body depend on the mass of the body, specific heat capacity, and temperature difference. as shown below

Q = cm(t₂-t₁) ........................ Equation 1

(Q1)

Q = cm(t₂-t₁)

Where Q = amount of heat absorbed, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature.

Given: m = 229.1 g = 0.2991 kg, t₁ = 25.0 °C, 32.50 °C

Constant: c = 4200 J/kg.°C

Substituting into equation 1

Q = 0.2991×4200(32.5-25)

Q = 1256.22(7.5)

Q = 9421.65 J

Q = 9.42 kJ.

Hence the heat absorbed = 9.42 kJ

(Q2)

Q = cm(t₂-t₁)

Where Q = amount of heat required, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature.

Given: m = 34 g = 0.034 kg, t₁ = 9 °C, t₂ = 23 °C

Constant: c = 4200 J/kg.°C

Q = 0.034×4200(23-9)

Q = 142.8(14)

Q = 1999.2 J

Q = 1.999 kJ.

Thus the Heat required = 1.999 kJ

4 0
3 years ago
What is the value of for this aqueous reaction at 298 K? <br><br>A+B↽⇀C+D ΔG°=12.86 kJ/mol<br><br>K=
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Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>

<em>R is gas constant = 8.314x10⁻³kJ/molK</em>

<em>T is absolute temperature = 298K</em>

<em>And K is equilibrium constant.</em>

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

<h3>The equilbrium constant is 179.6</h3>

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