Answer:
The velocity is
Explanation:
From the question we are told that
The initial speed is
The cross -sectional area of the first pipe is
The cross -sectional area of the second pipe is
Generally from continuity equation we have that
So
=>
=>
The magnitude of the force that the charged sphere exerts on the line of charge is 0.0181 N.
<h3>
Magnitude of force between the charges</h3>
Apply Coulomb's law of electrostatic force.
F = (kq1q2)/r²
where;
- q1 is charge 1 = 6.3 n C/m x 0.2 m = 1.26 nC
- q2 is charge 2 = -4 μC
- r is the distance between the charges = 5 cm = 0.05 m
F = (9 x 10⁹ x 1.26 x 10⁻⁹ x 4 x 10⁻⁶)/(0.05)²
F = 0.0181 N
Learn more about electrostatic force here: brainly.com/question/17692887
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the sugar dissolves, but is still there, just not visible
Answer:
The distance of the second sound intensity level is 28.12 m.
Explanation:
Given;
intensity of first sound level, I₁ = 110 dB
distance of first sound level, r₁ = 5 m
intensity of second sound level, I₂ = 95 dB
let the distance of second sound level = r₂
The intensity of the sound in W/m² is given as;
where;
I₀ is threshold of hearing = 1 x 10⁻¹² W/m²
for 110 dB to W/m²
for 95 dB to W/m²
The intensity of sound is related to distance as follows;
Now, determine the distance of the second sound intensity level
Therefore, the distance of the second sound intensity level is 28.12 m.