Answer:2800000j
Explanation:
For us to know the kinetic energy of the vehicle,
Where m is the mass
And v is the velocity
Then, K.E=1/2mv^2
While, K.E=1/2×3500×40^2
Therefore, our answer will now be
K.E=2800000j
Acceleration= change in velocity/time; 5/2.8 , so a=1.785714286
<span>Answer:
Let m = mass of cannon
Then
10000 = ma
a = 10000/m
v^2 = u^2 + 2as
v^2 = 0 + 2as
84^2 = 2(2.21)(10000/m)
84^2 m = 4.42(10000)
m = 6.264172336
= 6.26 kg
Part 2
Range = u^2sin(2x38)/g
= 84^2sin(76)/9.8
= 698.6129229
= 698.6 m</span>
Answer:
The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU
Explanation:
am = mvr= angular momentum
am4= 4mvt
am1= mvp1
Vt=1/4vp
Vp=4vt
am1= 4mvt
am1=am4
The circular solar orbital speed at 4.0AU is 1/4 (one fourth) that at 1.0AU
Most waves approach the shore at an angle. However, they bend to be nearly parallel to the shore as they approach it because when a wave reaches a beach or coastline, it releases a burst of energy that generates a current, which runs parallel to the shoreline.
- Most waves approach shore at an angle. As each one arrives, it pushes water along the shore, creating what is known as a longshore current within the surf zone.
- Waves approach the coast at an angle because of the direction of prevailing wind.
- The part of the wave in shallow water slows down, while the part of the wave in deeper water moves at the same speed.
- Thus when wave reaches a beach or coastline, it releases a burst of energy that generates a current, which runs parallel to the shoreline.
To know more about waves visit:
brainly.com/question/27831266
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