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3 years ago

7

Rainwater draining from a neighborhood street initially travels at 4 ft/s through a pipe with a cross-sectional area of 15.7 ft2

. This pipe connects down the street to another pipe with a cross-sectional area of 65.4 ft2. What would be the speed of the water as it moves through this larger pipe?

1 answer:

Fudgin [204]3 years ago

6 0

Answer:

The velocity is $v_2 = 0.96 \ ft/s$

Explanation:

From the question we are told that

The initial speed is $v_1 = 4 \ ft/s$

The cross -sectional area of the first pipe is $A_1 = 15.7 \ ft$

The cross -sectional area of the second pipe is $A_2 = 65.4 \ ft$

Generally from continuity equation we have that

$A_1 * v_1 = A_2 * v_2$

So

$v_2 = \frac{A_1 * v_1 }{A_2 }$

=> $v_2 = \frac{15.7 * 4 }{65.4 }$

=> $v_2 = 0.96 \ ft/s$

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Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

The first mass is $m_1 = 0.42kg$

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From the question we can see that at equilibrium the moment about the point where the string holding the bar (where $m_1 \ and \ m_2$ are hanged ) is attached is zero

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Making x the subject of the formula

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Also at equilibrium the moment about the point where the string holding the bar (where ( $m_1 +m_2$ ) and $m_3$ are hanged ) is attached is zero

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Angular velocity is usually measured with $\frac{radians}{sec}$ , so I'm going to use that to answer your question.

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