Answer:
Part a)
Part b)
Explanation:
Part A)
As we know that time period of the motion is given as
so we have
now at the point of maximum amplitude the force equation when Normal force is about to zero is given as
so we have
Part b)
Now if the amplitude of the SHM is 6.23 cm
and now at this amplitude if object will lose the contact then in that case again we have
so now we have
Answer:
The buoyant force is 9.8 N.
Explanation:
The buoyant force acting on the material is called upthrust, and can be determined as;
Upthrust = density of liquid x volume of object x gravitational force
So,
density =
⇒ mass = density x volume
= 4230 x 0.001
= 4.23
mass of the material = 4.23 kg
But,
weight = mass x gravitational force
weight = 41.5 N, and mass = 4.23 kg, then;
41.5 = 4.23 x g
g =
= 9.811
g = 9.8 m/
Upthrust = 1000 x 0.001 x 9.81
= 9.81 N
The buoyant force is 9.8 N.
It's B lol they are being forced apart but can't move because the are tied down
Answer:what are the answer options?
Explanation
Answer:
a = (v² − v₀²) / (2 (x − x₀))
Explanation:
v² = v₀² + 2a(x − x₀)
Subtract v₀² from both sides.
v² − v₀² = 2a(x − x₀)
Divide both sides by 2 (x − x₀).
(v² − v₀²) / (2 (x − x₀)) = a