The answer would be 11 because the x's 9 doesnt have to move because they're on the same point. If you take 7 away from -7 you get zero. Add 4 to that 7 and you get 11. Make sesnse?
Hope this helped!
<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>
<em><u>Solution:</u></em>
Given that,
![\text{ product of } 42.12 \text{ and } 10^3](https://tex.z-dn.net/?f=%5Ctext%7B%20product%20of%20%7D%2042.12%20%5Ctext%7B%20and%20%7D%2010%5E3)
Which means,
![42.12 \times 10^3](https://tex.z-dn.net/?f=42.12%20%5Ctimes%2010%5E3)
Here, the exponent of 10 is positive ( which is 3)
When the exponent is positive, we have to move the decimal point to right
When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10
Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12
Therefore,
![42.12 \times 10^3 = 42120](https://tex.z-dn.net/?f=42.12%20%5Ctimes%2010%5E3%20%3D%2042120)
Answer:
x = 3 x = 7 Okay well I got C. f(x) = x2 - 10x + 21 I got it because u subtract and add at the last part.
Step-by-step explanation:
Answer:
D i think
Step-by-step explanation: