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ANEK [815]
4 years ago
9

Here is the situation: A puck is resting on the floor of a large moving van. Assume that the floor of the van is frictionless. T

he van and the puck are initially at rest, then the van undergoes a positive uniform acceleration. Determine whether each statement below is:a. True b. False.
Physics
1 answer:
Ahat [919]4 years ago
3 0

Answer:

Statement 1: Someone outside the van sees the puck remain stationary with respect to the ground.

TRUE. This is because the puck relative to the ground initially was stationary. When the van starts to move forward or accelerate, the puck will tend to maintain its stationary state with the ground by moving in the opposite direction. This movement is only relative to the van and not the ground because the puck and the ground are at rest as the puck has no net force acting on it.

Someone in the van sees the puck move toward the front of the van.

FALSE. The puck has no net force acting in it so by newton's first law it should have no relative movement to the ground. In order to achieve this, the puck by newton's third law of motion must move in the opposite direction (backwards) as the van to maintain its stationary state with the ground.

The acceleration of the van with respect to the ground is > the acceleration of the puck with respect to the ground.

If the van turns to the right, the puck will hit the left wall.

WHAT DOES THIS HAVE TO DO WITH THE STATEMENTS? I'll assume the truck continues in a straight line and this statement if irrelevant. It does say "If"

The magnitude of the acceleration of the van with respect to the ground is = the magnitude of the puck's acceleration with respect to the van.

The puck is stationary with respect to the van during this acceleration.

FALSE

Explanation:

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GenaCL600 [577]

Answer:

a)θ=74.03°  (N-E)

b)t=1.56 hr

Explanation:

Given that

Plane speed = 200 km/h

Wind speed = 55 km/h

Now from diagram

V is the resultant velocity of plane

200^2=V^2+55^2

V=192.28 km/h towards north

From triangle ABC

cos\theta =\dfrac{55}{200}

θ=74.03°

Given that

d=300 km

We know that

d = V x t

300 = 192.28 x t

t=1.56 hr

7 0
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kupik [55]

Answer:

k=320N/m

Explanation:

Step one:

given data

Let the initial/equilibrum position be x

mass m1= 0.2kg

F1= 0.2*10= 2N

elongation e= 9.5cm= 0.095m

mass m2=1kg

F2=1*10= 10N

elongation e= 12cm= 0.12m

Step two:

From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F

F=ke

2=k(0.095-a)

2=0.095k-ka----------1

10=k(0.12-a)

10=0.12k-ka----------2

solving equation 1 and 2 simultaneously

 

   10=0.12k-ka----------2

-   2=0.095k-ka----------1

   8=0.025k-0

divide both side by 0.025

k=8/0.025

k=320N/m

5 0
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4 years ago
Which car has the most kinetic energy?
mixas84 [53]

Answer:

B. A car of mass 2000 kg with speed 7 m/s

Explanation:

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where m is the mass of the object and v is its speed.

From the formula, we see that the larger the mass and the speed of the object, the larger its kinetic energy. Among the choices given, we see that the car with largest mass and largest speed is car B, which has a mass of 2000 kg and speed of 7 m/s. Its kinetic energy is:

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We can verify that the other cars have smaller kinetic energy. In fact:

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- Car D: K=\frac{1}{2}(2000 kg)(3 m/s)^2=9,000 J

So, car B is the one which has most kinetic energy.

5 0
4 years ago
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