You need to get to class, which is 282 meters away. You can only walk in the hallway at about 2.0 m/s (if you go any faster, you
1 answer:
Answer:
Time, t = 141 seconds
Explanation:
Given that,
Distance between the class and the person, d = 282 m
Speed of the person, v = 2 m/s
We need to find the time taken by the person to get to your class. Let the time taken is t. The speed of the person is given by :
t = 141 seconds
So, the time taken by the person to get to your class is 141 seconds. Hence, this is the required solution.
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Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
v = 2 m/s
Hence, their speed after collision is 2 m/s.