BECUASE there are many subjects and to much pressure on the kids and sometimes learn things we don’t need to know
Answer:1) 100 gm mass should be placed at 95 cm mark.
2) Mass of 112.5 gm should be placed at 90 cm mark.
Explanation:
For equilibrium of the meter stick the sum of the moment's generated by the masses should be equal and opposite
Answer to part b)
Since a meter stick is 100 cm long and it is pivoted at it's center i.e at 50 cm
Thus
1) Moment generated by 100 gm mass about center =
Let a mass 'm' be placed at 90 cm mark thus moment it generates equals
Equating both the moments we get
Answer to part a)
Let the 100 grams weight be placed at a distance 'x' right of center
Moment generated by 100 grams weight equals
equating the moments of the forces we get
thus the mass of 100 gm should be placed at 95 cm mark in the scale.
Acceleration = ( final velocity - intial velocity ) / time
= (60-0)m/s / 3s
= 20 m/s2
the answer is a
What happens is that if u put gas in a ball and placed in a hot climate it will start burning Bc u have gas inside the ball
Answer:
Weight of the dog on surface of earth is 140.14 Newton.
Given:
mass of the dog = 14.3 kg
To find:
Weight of the dog = ?
Formula used:
Weight of the dog is given by,
W = mg
Where, W = weight of the dog
m = mass of the dog
g = acceleration due to gravity
Solution:
Weight of the dog is given by,
W = mg
Where, W = weight of the dog
m = mass of the dog = 14.3 kg
g = acceleration due to gravity
W = 14.3 × 9.8
W = 140.14 Newton
Weight of the dog on surface of earth is 140.14 Newton.