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2 years ago

What type of objects cannot pull to magmets

Physics

2 answers:

boyakko [2]2 years ago

7 0

Answer:

brass, copper, zinc and aluminum, wood, glass, and plastic

Explanation:

AleksAgata [21]2 years ago

4 0

Answer:

PLASTIC OBJECTS , COINS, SILVER,GOLD ETC.

Explanation:

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A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support syst

kramer

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2 years ago

What is the average speed in 4 seconds going 8 meters

gulaghasi [49]

Answer:

Explanation:

speed is define as rate of change of distance or displacement

v=s/t

s=8 m

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2 years ago

Read 2 more answers

A luge and its rider, with a total mass of 85 kg, emerge from adownhill track onto a horizontal straight track with an initial s

Verdich [7]

(1) Through the Second Law of motion, the equation for Force is:

F = m x a

Where m is mass and a is acceleration (deceleration)

(2) Distance is calculated through the equation,

D = Vi^2 / 2a

Where Vi is initial velocity

(3) Work is calculated through the equation,

W = F x D

Substituting the known values,

Part A:

(1) F = (85 kg)(2 m/s^2) = 170 N

(2) D = (37 m/s)^2 / (2)(2 m/s^2) = 9.25 m

(3) W = (170 N)(9.25 m) = 1572.5 J

Part B:

(1) F = (85 kg)(4 m/s^2) = 340 N

(2) D = (37 m/s)^2 / (2)(4 m/s^2) = 4.625 m

(3) W = (340 N)(4.625 m) = 1572.5 J

7 0

2 years ago

A rocket of mass 1000kg uses 5kg of fuel and oxygen to produce exhaust gases ejected at 500m/s calculate the increase its veloci

Vlad [161]

Answer:

Approximately $\rm 2.5\; m \cdot s^{-1}$ .

Explanation:

Let the increase in the rocket's velocity be $\Delta v$ . Let $v_0$ represent the initial velocity of the rocket. Note that for this question, the exact value of $v_0$ doesn't really matter.

The momentum of an object is equal to its mass times its velocity.

Mass of the rocket with the 5 kg of fuel: $1000$ .
Initial velocity of the rocket and the fuel: $v_0$ .
Hence the initial momentum of the rocket: $1000\,v_0$ .

Mass of the rocket without that 5 kg of fuel: $1000 - 5 = 995$ .
Final velocity of the rocket: $v_0 + \Delta v$ .
Hence the final momentum of the rocket: $995\,(v_0 + \Delta v)$ .

Mass of the 5 kg of fuel: $5$ .
Final velocity of the fuel: $v_0 - 500$ (assuming that the the 500 m/s in the question takes the rocket as its reference.)
Hence the final momentum of the fuel: $5\,(v_0 - 500)$ .