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Ray Of Light [21]
4 years ago
14

10 Pts + Brainliest Which statement can you conclude is true from the given information?

Mathematics
2 answers:
Nostrana [21]4 years ago
7 0
The correct answer is A
B is wrong because IAJ is not an angle because it doesn’t have a line that connects I and A
C is wrong because the segments are not in according order it would be correct if it said IJ = KJ
D is wrong because it says that Point a is the midpoint however J is the midpoint for both intersecting lines.
Please mark brainliest
tekilochka [14]4 years ago
6 0

Answer:

C

Step-by-step explanation:

If a line bisects a segment, both sides of the segment are equal. Therefore, IJ and JK have the same length, and are equal.

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Which of the following ordered pairs should be tested to determine which side to shade when graphing the inequality
Veseljchak [2.6K]

Answer:

A

Step-by-step explanation:

Pick any point on any side of the line. substitute X and Y in the inequality for (x,y)-the point you chose. If you simplify and the inequality is true, shade in that side. If it is false, shade in the other side.

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3 years ago
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Find the Slope of the line.<br> m =
anzhelika [568]

Answer: 4/5

Step-by-step explanation:

Rise over run

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The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.
Illusion [34]

Answer:

100

Step-by-step explanation:

6 0
3 years ago
Please find the perimeter and area of these shapes
ladessa [460]

Answer:

ABC shaded area = 36\pi - 72   cm²

ABC shaded area perimeter = 6\pi +12\sqrt{2}    cm

ABCD area = \dfrac52 \pi  cm²

ABCD perimeter = 3\pi +2   cm

Step-by-step explanation:

<u>Shape ABC</u>

Assuming you want the area and perimeter of the shaded part of the shape only...

<u>Area</u>

Area of a sector = \dfrac12r^2\theta (where r is the radius and \theta<em> </em>

⇒ area of a sector = \dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi  \ \textsf{cm}^2

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36\pi - 72 cm²

<u>Perimeter</u>

Arc length = r\theta (where r is the radius and \theta<em> </em>

⇒ arc length = 12\times\dfrac12\pi =6\pi  \ \textsf{cm}

Hypotenuse of triangle = \sqrt{a^2+b^2} (where a and b are the legs of the right triangle)

⇒ hypotenuse = \sqrt{12^2+12^2} =12\sqrt{2} cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = 6\pi +12\sqrt{2}  cm

<u>Shape ABCD</u>

<u>Area</u>

Area of a semicircle = \dfrac12 \pi r^2 (where r is the radius)

⇒ area of large semicircle ABC = \dfrac12 \times \pi \times 2^2=2\pi  \ \textsf{cm}^2

⇒ area of small semicircle AD = \dfrac12 \times \pi \times 1^2=\dfrac12\pi  \ \textsf{cm}^2

⇒ area of shape ABCD = \dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2

<u>Perimeter</u>

1/2 circumference = \pi r

⇒ perimeter = 2\pi +2+\pi=3 \pi+2 \ \textsf{cm}

7 0
2 years ago
Calc AB multiple choice. Please help
Vinvika [58]
You start off with 4*(cos(x+(pi/3)))

Let's place the 4 aside for the time being:

Cos(u+j) = cos(u)*cos(j) - sin(u)*sin(j)

cos(x+(pi/3)) = cos(x)*cos(pi/3) - sin(x)*sin(pi/3)

cos(x+(pi/3)) = cos(x)/2 - (sqrt(3)/2)*sin(x)

Multiplying by the 4 we put aside:

4*cos(x+(pi/3)) = 2*cos(x) - 2*sqrt(3)*sin(x)

The correct answer is B
3 0
3 years ago
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