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4 years ago

10 Pts + Brainliest Which statement can you conclude is true from the given information?

Mathematics

2 answers:

Nostrana [21]4 years ago

7 0

The correct answer is A
B is wrong because IAJ is not an angle because it doesn’t have a line that connects I and A
C is wrong because the segments are not in according order it would be correct if it said IJ = KJ
D is wrong because it says that Point a is the midpoint however J is the midpoint for both intersecting lines.
Please mark brainliest

tekilochka [14]4 years ago

6 0

Answer:

Step-by-step explanation:

If a line bisects a segment, both sides of the segment are equal. Therefore, IJ and JK have the same length, and are equal.

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Which of the following ordered pairs should be tested to determine which side to shade when graphing the inequality

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Step-by-step explanation:

Pick any point on any side of the line. substitute X and Y in the inequality for (x,y)-the point you chose. If you simplify and the inequality is true, shade in that side. If it is false, shade in the other side.

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3 years ago

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The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.

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3 years ago

Please find the perimeter and area of these shapes

ladessa [460]

Answer:

ABC shaded area = 36 $\pi$ - 72 cm²

ABC shaded area perimeter = $6\pi +12\sqrt{2}$ cm

ABCD area = $\dfrac52 \pi$ cm²

ABCD perimeter = $3\pi +2$ cm

Step-by-step explanation:

Shape ABC

Assuming you want the area and perimeter of the shaded part of the shape only...

Area

Area of a sector = $\dfrac12r^2\theta$ (where r is the radius and $\theta$

⇒ area of a sector = $\dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi \ \textsf{cm}^2$

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36 $\pi$ - 72 cm²

Perimeter

Arc length = $r\theta$ (where r is the radius and $\theta$

⇒ arc length = $12\times\dfrac12\pi =6\pi \ \textsf{cm}$

Hypotenuse of triangle = $\sqrt{a^2+b^2}$ (where a and b are the legs of the right triangle)

⇒ hypotenuse = $\sqrt{12^2+12^2} =12\sqrt{2}$ cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = $6\pi +12\sqrt{2}$ cm

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Area

Area of a semicircle = $\dfrac12 \pi r^2$ (where r is the radius)

⇒ area of large semicircle ABC = $\dfrac12 \times \pi \times 2^2=2\pi \ \textsf{cm}^2$

⇒ area of small semicircle AD = $\dfrac12 \times \pi \times 1^2=\dfrac12\pi \ \textsf{cm}^2$

⇒ area of shape ABCD = $\dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2$

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1/2 circumference = $\pi r$

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2 years ago

Calc AB multiple choice. Please help

Vinvika [58]

You start off with 4*(cos(x+(pi/3)))

Let's place the 4 aside for the time being:

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Multiplying by the 4 we put aside:

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The correct answer is B

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