Answer:
3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter
Step-by-step explanation:
Rashid pastries (R)
Mikhail pastries (M)
Rashid and Mikhail submitted a total of x pastries
R+M=x (I)
Rashid made 2/3 as many pastries as Mikhail
(2/3)*R=M (II)
Using II in I
R+(2/3)*R=x
(5/3)*R = x
R=(3/5)*x (III)
Using III in I
(3/5)*x+M=x
M=x-(3/5)*x
M=(2/5)*x (IV)
Mikhail filo dough (MF)
Mikhail shortcrust dough (MS)
Rashid filo dough (RF)
Rashid shortcrust dough (RS)
Mikhail used filo dough for all of his pastries
MF=M
MS=0
Rashid used shortcrust dough for all of his pastries
RS=R
RF=0
Filo dough (FD)
FD=RF+MF=0+MF=MF=M (V)
5/8 of the filo dough pastries were brushed with olive oil
pastries brushed with olive oil (OI)
(5/8)*FD=OI
Using V
(5/8)*M=OI
Using IV
(5/8)*(2/5)*x=OI
(1/4)*x=OI (VI)
pastries brushed with butter (B)
Pastries made out of filo dough are brushed with either olive oil or butter (but not both)
FD=OI+B
B=FD-OI
Using V and VI
B= M - (1/4)*x
Using IV
B = (2/5)*x - (1/4)*x
B= (3/20)*x
3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter
Answer:
Step-by-step explanation:
a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.
b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).
c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following
where 
Answer:
Plot these points:(-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) (3,3) (4,5)
Step-by-step explanation:
You need to substitute your x values into the x of the equation y=2(3)-3 to find the y value...
Answer:
x=82
Step-by-step explanation:
53+45=98
180-98=82
