1.302 moles of carbon dioxide would have to be added
<h3>Further explanation</h3>
The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient
The equilibrium constant is based on the concentration (Kc) in a reaction
pA + qB -----> mC + nD
![\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%20%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKc%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D%20)
While the equilibrium constant is based on partial pressure
![\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}](https://tex.z-dn.net/?f=%20%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKp%20~%20%3D%20~%20%5Cfrac%20%7B%5BpC%5D%20%5E%20m%20%5BpD%5D%20%5E%20n%7D%20%7B%5BpA%5D%20%5E%20p%20%5BpB%5D%20%5E%20q%7D%7D%7D%7D%20)
The value of Kp and Kc can be linked to the formula '
R = gas constant = 0.0821 L.atm / mol.K
=n = number of product coefficients-number of reactant coefficients
An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O
- We determine Kc (constant concentration)
- the amount of carbon monoxide to 0.300 mol
Reaction :
CO +H₂O ⇔ CO₂ + H₂
initially 0.2 0.2 0.75+x 0.75
reaction 0.1 0.1 0.1 0.1
product 0.3 0.3 0.65+x 0.65
<h3>Learn more</h3>
an equilibrium constant brainly.com/question/9173805
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Calculate the value of the equilibrium constant, Kc
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Concentration of hi at equilibrium
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Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient
