Based on this, Individual electrons in graphene have almost no mass compared to the other particles.
The material graphene consists of a single layer of carbon atoms arranged in a hexagonal lattice.
Electrons flowing through graphene can be scattered from impurities (such as foreign atoms in the lattice), from other electrons and from lattice vibrations known as phonons.
What happens to the electrons in graphene?
According to the researchers, such high values are a result of the photo thermoelectric effect. “It turns out that when you shine a light on graphene, the electrons in the material heat up, and remain hot, while the underlying carbon lattice remains cool,”
Why are electrons massless in graphene?
Yes, low energy electrons and holes in graphene can be thought of as massless because of the linear dispersion of the band structure near the K points.
This is an analogy to the relativistic energy dispersion E2=P2C2+M2C4, which becomes linear in momentum for m=0.
To learn more about electrons here
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Answer:
The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa
Explanation:
<u>Step 1</u>: Calculate the volume of a spherical container V
V = (4π*r³)/3
r = (3V/4π)^1/3
2r = d = 2*(3V/4π)^1/3
with r= radius
with d= diameter
The diameter is:
d= 2*(3V/4π)^1/3
d= 2*(3*100cm³/4π)^1/3
d= 5.76 cm
<u>Step2 </u>: Define the free path lambda λ of argon
with λ =k*T/ σp
with p = kT/σλ
with T= temperature = 20°C = 293.15 Kelvin
with k = Boltzmann's constant = 1.381 * 10^-23 J/K
with p = the atmospheric pressure
with σ = 0.36 nm²
p = kT/σλ
p = (1.38 * 10^-23 J*K^-1 * 1Pa *m³/1J)*(293,15K) /(0.36 nm²*(10^-9/ 1nm)² *(5.76cm* 10^-2m/1cm)
p = 0.195 Pa
The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa
K2O + CaBr2 ---> CaO + 2 KBr
Unable to read second question properly sorry
Mole percent is the percentage of the total moles that is of a particular component.
