Question:
What two forces are balanced in what we call gravitational equilibrium?
A) the electromagnetic force and gravity
B) outward pressure and the strong force
C) outward pressure and inward gravity
D) the strong force and gravity
E) the strong force and kinetic energy
Answer:
The correct answer is C) Outward Pressure and Inward gravity
Explanation:
Gravitational equilibrium is a balance between the inward pull of gravity and the outward push of internal gas pressure. It also refers to the condition of a star in which the weight of overlying layers at each point is balanced by the total pressure at that point.
As the weight increases in the lower layers of the sun, the pressure also increases to maintain this balance. So you find that the outward push of pressure balances the inward pull of gravity thus creating an equilibrium.
Why is gravitational equilibrium important?
The simple answer is <u>balance. </u> If for instance the sun as a stable star (which has gravitational equilibrium) loses it's balance, it becomes highly unstable and prone to violent outbursts. These outbursts are caused by the very high radiation pressure at the star's upper layers, which blows significant portions of the matter at the "surface" into space during eruptions that may rage for several years. Of course such a condition is adverse to the existence and support of life.
Cheers!
Answer:
yes, if you're going at 120 km and you saw the wall that late then it wouldn't me possible to decrease 12 meters in 5 seconds and not hit the wall that's only 60 meters away
Explanation:
Taking shorter showers, turning off the lights when you aren't in a room, use energy efficient lightbulbs like LED's, use the air conditioning only when you really need it, and use the heat less in the winter.
For item#1 , see attached picture, there is a voltage source, a resistor and wire (where current flow).
For item#2, we use the formula V=IR where "V" is for the voltage, "I" is for the current and "R" for the resistance
Solving for I:
I = v/r
I = 45volts/15k ohms
I=3 mA
For item#3, power is P=VI
p = 45volts * 3ma
P = 0.135 Watts