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Goryan [66]
3 years ago
11

E) VAVC

Physics
1 answer:
gogolik [260]3 years ago
7 0

Answer:

b) tan a = 3

Explanation:

Draw a free body diagram (see attached).

There are three forces acting on the insect.  Weight downwards, normal force towards the center of the hemisphere, and friction tangent to the surface.

Sum of the forces in the radial direction:

∑F = ma

N − mg cos α = 0

N = mg cos α

Sum of the forces in the tangential direction:

∑F = ma

μN − mg sin α = 0

Substituting:

μ(mg cos α) − mg sin α = 0

μ cos α − sin α = 0

μ cos α = sin α

μ = tan α

The maximum possible value of the angle is such that its tangent is equal to the coefficient of friction.

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Suppose a car manufacturer tested its cars for front-en4 collisions by hauling them up on a crane and dropping then; from a cert
Brrunno [24]

Answer:

a

Generally from third equation of motion we have that

v^2 =  u^2 + 2a[s_i - s_f]

Here v is the final speed of the car

u is the initial speed of the car which is zero

s_i is the initial position of the car which is certain height H

s_i is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

So

v^2 = 0 + 2g[H - 0]

=> v  =  \sqrt{ 2 g H}

b

H  =  9.86 \  m

Explanation:

Generally from third equation of motion we have that

v^2 =  u^2 + 2a[s_i - s_f]

Here v is the final speed of the car

u is the initial speed of the car which is zero

s_i is the initial position of the car which is certain height H

s_i is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

So

v^2 = 0 + 2g[H - 0]

=> v  =  \sqrt{ 2 g H}

When v  = 50 \  km/h = \frac{50 *1000}{3600} = 13.9 \  m/s we have that

13.9  =  \sqrt{ 2 g H}

=> H  =  \frac{13.9^2}{2 *  9.8}

=> H  =  9.86 \  m

6 0
3 years ago
A solid block of mass m2 = 1.14 kg, at rest on a horizontal frictionless surface, is connected to a relaxed spring (with spring
borishaifa [10]

Answer:

v = 1 m/s

Explanation:

from the principle of conservation of momentum, we have following relation

initial momentum = final momentum

m_{1}v_{1}+m_{2}v_{2} = (m_{1}+m_{2})v^{2}

where

m1 = 1.14 kg

v1 = 2.0 m/s

m2 = 1.14 kg

v2  = 0 m/s

putting all value in the above equation

1.14 *2.0+ 0 =(1.14+1.14)v^{2}

v =\frac{1.14*2.0}{1.14+1.14}

v = 1 m/s

4 0
3 years ago
5. A car accelerates from 0 to 72 km/hour in 8.0 seconds. What is the car's acceleration?
MA_775_DIABLO [31]

Answer:

2.5 m/s

Explanation:

There are calculators online that can help you easily calculate the accerlation.

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B low frequency it is the lowest frequency
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