a jet plane traveling 1890 km/h pulls out of a dive by moving in an arc of radius 5.20km. what is planes acceleration in g's
1 answer:
Answer:
Explanation:
Unit conversions:
1890 km/h = 1890 km/h * 1000m/km * 1/3600 h/s = 525 m/s
5.2 km = 5200 m
Assume that the jets is traveling in perfect circular motion, we can calculate the centripetal acceleration of the motion:
where v = 525m/s is the velocity of the jet and r = 5200 is the radius of the arc
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Explanation:
The given data is as follows.
Mass, m = 75 g
Velocity, v = 600 m/s
As no external force is acting on the system in the horizontal line of motion. So, the equation will be as follows.
where, = mass of the projectile
= mass of block
v = velocity after the impact
Now, putting the given values into the above formula as follows.
=
v = 0.898 m/s
Now, equation for energy is as follows.
E =
=
= 13500 J
Now, energy after the impact will be as follows.
E' =
= 20.19 J
Therefore, energy lost will be calculated as follows.
= E E'
= (13500 - 20) J
= 13480 J
And, n =
=
= 99.85
= 99.9%
Thus, we can conclude that percentage n of the original system energy E is 99.9%.