What is the Interquartile Range for the following data set?<br>
{5, 6, 7, 3,9,8, 3, 1,6,7,7)
DochEvi [55]
Answer:
sorting, we have 1 3 3 5 6 6 7 7 7 8 9. The middle number is 6. The lower quartile is 3. The upper is 7. 7-3=4.
Step-by-step explanation:
<span>∫(sinx cosx)^2dx = ∫(1/2sin 2x)^2 dx = 1/4∫sin^2 2x dx = 1/4∫1/2(1 - cos 4x)dx = 1/8∫(1 - cos 4x) dx = 1/8[x - sin 4x / 4] + c = 1/32(4x - sin 4x) + c
</span>
Answer:
1/6
Step-by-step explanation:
Perpendicular lines have slopes whose product is -1. That is ...
-6m = -1
m = 1/6 . . . . . divide by -6
X can be any real number
As long as it is to the power of 0, it will equal one. And because 6^0 = 1, 1^x can be any positive number, and it will still give you one.
As stated by WojtekR, even negative numbers can get 1
x = - 5
(6^0)^-5 = 1^-5 = 1/1 = 1
~ Thanks @WojtekR
