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son4ous [18]
2 years ago
8

How many grams of aluminum oxide will you need to start with in order to make 6500 g of aluminum hydroxide?

Chemistry
2 answers:
REY [17]2 years ago
8 0

Answer:

56.7 grams of aluminum oxide (AI²O³) are produced.Need a fast expert's response.

kherson [118]2 years ago
3 0

Answer:

Explanation:

2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.

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What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

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Mole fraction for solute = 0.1, or 10%

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