All categories

3 years ago

How many sulfur atoms are present in 100 grams of this compound? Report your answer to three significant figures.

Chemistry

1 answer:

kap26 [50]3 years ago

7 0

Answer:

1.88 × 10²⁴ atoms

Explanation:

Step 1: Given data

Mass of sulfur: 100 g

Step 2: Calculate the moles corresponding to 100 g of sulfur

The molar mass of sulfur is 32.07 g/mol. The moles corresponding to 100 g of sulfur are:

100 g × (1 mol/32.07 g) = 3.12 mol

Step 3: Calculate the number of atoms in 3.12 moles of sulfur

We will use Avogadro's number: there are 6.02 × 10²³ atoms of sulfur in 1 mole of sulfur.

3.12 mol × (6.02 × 10²³ atoms/1 mol) = 1.88 × 10²⁴ atoms

You might be interested in

10 ejemplos de disoluciones identificando el soluto y el solvente y el tipo de disolucion que corresponde

Keith_Richards [23]

Answer:

hije51k 5jk45679349fjvokhffgpv9ü

4 0

2 years ago

Which chemical equation represents the reaction of an Arrhenius acid and an Arrhenius base?

Komok [63]

The chemical equation that represents the reaction of an Arrhenius acid and an Arrhenius base is 1) HC2H3O2 (aq) + NaOH (aq) ---> NaC2H3O2 (aq) + H2O (I)

6 0

3 years ago

Read 2 more answers

1 kg of water (specific heat = 4184 J/(kg K)) is heated from freezing (0°C) to boiling (100°C). What is the change in thermal en

Andrews [41]

Answer: 1560632 joules

Explanation:

The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = ?

Mass of frozen water (ice) = 1kg

C = 4184 J/(kg K)

Φ = (Final temperature - Initial temperature)

= 100°C - 0°C = 100°C

Convert 100°C to Kelvin

(100°C + 273) = 373K

Then, Q = MCΦ

Q = 1kg x 4184 J/(kg K) x 373K

Q = 1560632 joules

Thus, the change in thermal energy is 1560632 joules

5 0

3 years ago

When will a seed begin to germinate?

Vlada [557]

When it has sunlight and water

4 0

3 years ago

Read 2 more answers

In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

olga nikolaevna [1]

Answer:

a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

$A=\pi ^{1/3} (6V)^{2/3}$

The area of the 10.0 cm³-sphere is:

$A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}$

The area of each 1.25 cm³-sphere is:

$A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}$

The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²

The ratio of 8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00

Since the surface area is doubled, the second run will be faster.

6 0

3 years ago