It is possible to rate your active reading skills either by using a number is a specific rate or by using a word that qualifies your performance.
<h3>What are active reading skills?</h3>
Active reading skills are a set of skills that help you read actively; this means skills to effectively read a text and understand it.
<h3>How to rate your reading skills?</h3>
In this case, you are asked to rate your ability to pay attention to your understanding, thoughts, and questions while reading. To do this you can:
Rate using numbers:
- Select a specific scale rating such as 1 to 5 or 1 10.
- Analyze honestly if you used this ability while reading the text.
- Give yourself a number. For example, if you apply this skill only sometimes while reading you can rate yourself 5 out of 10.
Rate using words:
- Select the types of words that you will use, the most common ones are frequency words such as always, sometimes, and never.
- Analyze honestly your performance.
- Find the word that best fits it.
Learn more about rate in: brainly.com/question/2278897
The reaction is actually endothermic because delta H is positive, indicating that it absorbing heat.
The appropriate answer is d. the high specific heat capacity of water. This unique quality of water makes it suitable as an organic solvent. Specific heat capacity is the energy required to change one gram of a substance by one degree. Organic processes need to be carried out at a specific temperature. The high specific heat capacity of water ensures that environmental changes in temperature.
Answer:
Keqq = 310
Note: Some parts of the question were missing. The missing values are used in the explanation below.
Explanation:
<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>
Using the formula ΔG° = -RT㏑Keq
㏑Keq = ΔG°/(-RT)
where ΔG° = ΔH° - TΔS°
㏑Keq = ΔH° - TΔS°/(-RT)
㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)
㏑Keq = -14221.2/-2478.968175
㏑Keq = 5.73674166
Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶
Keq = 310.05
To get the molecular formula we use the individual atomic masses of the atoms making the molecule. Hence, to get the factor by which the empirical formula is multiplied, we divide molar mass by the total of the mass of the atoms making the empirical formula.
(C2H7) the mass of one carbon atoms is 12 so two atoms add up to 24. The mass of one hydrogen atom is 1 a.m.u thus 7 atoms give a total of 7 a.m.u. The sum of the two types of atoms is 24+7= 31
Molar mass=62.18
62.18/31=2.0
Hence, (C2H7) 2=C4H14
