Complete question is;
A hot plate with a temperature of 60 °C will be cooled by adding 50 triangular profile needle blades (k = 204 W/m.K) with a length of 54 mm and diameter 10 mm. According to the ambient temperature 20 °C and the heat transfer coefficient on the surface 20 W/m².K. Calculate,
a-) Wing efficiency
b-) Total heat transfer rate (W) from the wings,
c-) Calculate the effectiveness of a wing.
Answer:
A) Efficiency = 96.05 %
B) Total heat transfer rate = 166.68 W/m
C) Wing Effectiveness = 10.42
Explanation:
Please find attached explanation for all the answers given.
Answer: I am not for sure
Explanation:
Answer:
Explanation:
The formula for critical stress is


K is the plane strain fracture toughness
Y is dimensionless parameters
We are to Determine the Critical stress
Now replacing the critical stress with 54.8
a with 0.2mm = 0.2 x 10⁻³
Y with 1

The fracture will not occur because this material can handle a stress of 2186.20Mpa before fracture. it is obvious that is greater than 2023Mpa
Therefore, the specimen does not failure for surface crack of 0.2mm
The employer must inform employees and their representatives of their right to examine and copy all abatement documents submitted to the Agency. ... The employer must comply with an employee's or employee representative's request to examine and copy abatement documents within 5 working days of receiving the request.
Answer:
see explaination for all the answers and full working.
Explanation:
deflection=8P*DN/Gd^4
G(for steel)=70Gpa=70*10^9N/m^2=70KN/mm^2
for outer spring,
deflection=8*3*50^3*5/(70*9^4)=32.66mm
for inner spring
deflection=8*3*30^3*10/(70*5^4)=148.11mm
max stress=k*8*P*C/(3.14*d^2)
for outer spring
c=50/9=5.55
k=(4c-1/4c-4)+.615/c=1.2768
max stress=1.2768*8*3*5.55/(3.14*9^2=.66KN.mm^2
for inner spring
c=6
k=1.2525
max stress=2.29KN/mm^2