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4 years ago

List fabrication methods of composite Materials.

Engineering

1 answer:

Cloud [144]4 years ago

8 0

Answer:

Fabrication method of composite materials varies for one product of material to other product. It is basically developed to meet the product requirement.

The fabrication of composite parts are depends upon different factors that are:

Depend on the Characteristics of strengthening and matrices.
The details of the product and the shape and size also.
Application or end uses.

Types of fabrication methodologies are :

Press molding
Compression molding
Contact mold
Open molding
Tube rolling

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3 years ago

The rotor is driven at ????m = 120π rad/sec. If the stator winding carries a current of 5 A (rms) at 60 Hz, determine the instan

Levart [38]

Answer:

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3 years ago

Based on experimental observations, the acceleration of a particle is defined by the relation a = –(0.1 + sin x/b), where a and

Allisa [31]

Answer:

a) v = +/- 0.515 m/s

b) x = -0.098164 m

c) v = +/- 1.005 m/s

Explanation:

Given:

The relationship for the acceleration is given as follows:

a = - (0.1 + sin(x/b))

Where, b = 0.98

- IVP is v = 1 m/s @ x = 0

Find:

(a) the velocity of the particle when x = -1 m

(b) the position where the velocity is maximum

Solution:

- We will compute the velocity by integrating a by dt.

a = v*dv / dx = - (0.1 + sin(x/0.98))

- Separate variables:

v*dv = - (0.1 + sin(x/0.98)) . dx

-Integrate from v = 1 m/s to v and @ x = 0 to x:

0.5*(v^2) = - (0.1*x - 0.98*cos(x/0.8)) - 0.98 + 0.5

0.5*v^2 = 0.98*cos(x/0.98) - 0.1*x - 0.48

- Evaluate at, x = -1

0.5*v^2 = 0.98 cos(-1/0.98) + 0.1 -0.48

v = sqrt (0.2651155)

v = +/- 0.515 m/s

- v = v_max when a = 0. Set the given expression to zero and solve for x:

-0.1 = sin(x/0.98)

x = -0.98*0.1002

x = -0.098164 m

- Hence now evaluate velocity through the derived expression:

v^2 = 1.96 cos(-0.098164/0.98) -0.96 -0.2*-0.098164

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3 years ago

An environmental engineer is considering three methods for disposing of a nonhazardous chemical sludge: land application, fluidi

padilas [110]

Answer:

Explanation:

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The annual worth of land application = $ 29,017.54 + $ 95,000 - $ 2,456.95

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The annual worth of land Incineration = $ 211,283.85

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The land application has the least cost , hence it is preferred .

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3 years ago