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Answer:
(A) the thermal efficiency of this engine is 66.44 %
(B) the power delivered by the engine in watts is 664,400 W
(C) The rate at which heat is rejected to the cold temperature sink is 335.6 kJ/s.
Explanation:
Given;
Input Heat received by the engine, = 1000 kJ/s
hot temperature, = 600 ⁰C = 600 + 273 = 873 K
cold temperature, = 20 ⁰C = 20 + 273 = 293 K
(A) the thermal efficiency of this engine;
(B) the power delivered by the engine in watts;
(C) The rate at which heat is rejected to the cold temperature sink;
Answer:58.28 N
Explanation:
Given data
Now velocity of jet at height of 2m
equating them
W=
W=
W=58.28 N