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OLga [1]
3 years ago
13

Tech A says that coolant circulates through some intake manifolds to help warm them up. Tech B says that some intake manifolds u

se an electric heater grid to warm up the intake air. Who is corr
Engineering
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

Both Tech A and Tech B are correct.

Explanation:

In order to ensure that some intake manifolds have coolant running through them to assist them to warm up and to also ensure that an electric heater grid is used in some intake manifolds to warm up the intake air, a preheat grid is positioned between the intake manifold and throttle body.

This therefore implies that both Tech A and Tech B are correct. That is, it is true that coolant circulates through some intake manifolds to ensure that they warm up. And it is also true that some intake manifolds use an electric heater grid to warm up the intake air. This however occurs when a preheat grid is positioned between the intake manifold and throttle body.

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Explain The Basic Difference Between Bs2 And Bs3 Engine.​
snow_tiger [21]

Answer:

The main difference between the bs2 and bs3 engine is to present in the catalytic converter. And in bs2 engines the catalytic converter is does not used for the formation of hc and co. In bs3 engine there is no harmful emissions in the hc and co

3 0
2 years ago
Technician A says high resistance causes an increase in current flow. Technician B says a higher than
Kryger [21]

The correct statement is: a higher than a normal voltage drop could indicate high resistance. Technician B is correct.

<h3>Ohm's law</h3>

Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical conditions are constant. Mathematically, it is expressed as

V = IR

Where

V is the potential difference

I is the current

R is the resistance

<h3>Technician A</h3>

High resistance causes an increase in current flow

V = IR

Divide both side by I

R = V / I

Thus, technician A is wrong as high resistance suggest low current flow

<h3>Technician B</h3>

Higher than normal voltage drop could indicate high resistance

V = IR

Thus, technician B is correct as high voltage indicates high resistance

<h3>Conclusion </h3>

From the above illustration, we can see that technician B is correct

Learn more about Ohm's law:

brainly.com/question/796939

8 0
2 years ago
6. What are the potential consequences if a business does not follow regulations? (1 point)
dimaraw [331]

Answer:

all of the above

Explanation:

6 0
3 years ago
What is the worlds fastest car
Aneli [31]

Answer:

Thrust SSC

Explanation:

You can look it up

3 0
3 years ago
Read 2 more answers
A non-inductive load takes a current of 15A at 125V. An inductor is then connected in series in order that the same current shal
Norma-Jean [14]

Answer:

The inductance of the inductor is 0.051H

Explanation:

From Ohm's law;

  V = IR .................. 1

The inductor has its internal resistance referred to as the inductive reactance, X_{L}, which is the resistance to the flow of current through the inductor.

From equation 1;

V = IX_{L}

X_{L} = \frac{V}{I} ................ 2

Given that; V = 240V, f = 50Hz, \pi = \frac{22}{7}, I = 15A, so that;

From equation 2,

X_{L}= \frac{240}{15}

    = 16Ω

To determine the inductance of the inductor,

X_{L} = 2\pifL

L = \frac{X_{L} }{2 \pi f}

  = \frac{16}{2*\frac{22}{7}*50 }

 = 0.05091

The inductance of the inductor is 0.051H.

4 0
3 years ago
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