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Answer:
Rebounce angle is 345°
Rebounce speed is 989.95m/s
Explanation:
Calculate the x component of the velocity of the bullet before impact by using the following relation:
Vbx= Vb Cos thetha
Here, is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°
Substituting
Vbx = Cos15 ×1400 = 1352.30m/s
Calculate the y component using the relation:
Vby = Vo Sin theta
Vby = sin 15° × 1400
Vby = 362.35m/s
The rebounce angle = 360 - incidence angle
Rebounce angle =( 360 - 15)° = 345°
The rebound speed V' = Vby - Vbx
V' = (1352.30 - 362.35)m/s
V' = 989.95 m/s
Answer:
1.2 kg
Explanation:
Let UP ramp be the positive direction
F = ma
T - Wt || - Ff = m(0)
mg - Μgsinθ - μΜgcosθ = 0
m(9.8) - 13sin35 - 0.36(13)cos35 = 0
m = 13(sin35 + 0.36cos35) / 9.8
m = 1.15205... ≈ 1.2 kg
Answer:
6.4m/s
Explanation:
The total mechanical energy of the man is 1780J.
This mechanical energy is the energy due to the motion of the body and it is a form of kinetic energy.
Also, mass = 87kg
Kinetic energy =
m v²
m is the mass
v is the velocity
1780 =
x 87 x v²
v² = 40.9
v = 6.4m/s