two object gravitationally attract with a force of 20N.if the distance between the two object centers is doubled, then what is t
1 answer:
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Answer:
The graph is shown below.
The athlete's speed at the finish line is 11 m/s
Total distance covered is 82.5 m.
Explanation:
The graph of speed versus time is drawn below.
Acceleration in the first 5 seconds, m/s²
From the graph, the slope of line OA is the acceleration in the first 5 seconds.
Slope of line OA is given as:
Now, the length AD is nothing but speed at point A or B as AB is a straight line.
Therefore, the speed when crossing the finish line is the speed at B which is equal to 11 m/s.
Distance covered is given by the total area under the graph.
The total area can be divided into two shapes; a triangle and a rectangle.
The area under the graph is the sum of areas of triangle OAD and rectangle ABCD.
Area of triangle OAD is,
Area of rectangle ABCD is,
Therefore, the total distance covered till the finish line is given as:
Answer:
The gravitational force of an object that has half the mass is C) 9G.
Explanation:
Newton's Law of Gravitation:
We can see that the gravitational force, , and mass (let's combine M * m into just "m"),
, are <u>directly proportional</u> to each other.
This means that <em>if </em><em> </em><em>increases</em><em>, </em>
<em> also </em><em>increases</em>.
Therefore, <u>if the mass is halved</u>, that means that <u>the gravitational force is also going to be halved</u>.
The answer is 18G / 2 = 9G, which corresponds to answer C) 9G.