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2 years ago

12

two object gravitationally attract with a force of 20N.if the distance between the two object centers is doubled, then what is t

he new force?

1 answer:

Usimov [2.4K]2 years ago

8 0

Gravity decreases with the square of the distance, so the new force is (20)/(2*2) = 5N.

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In a “minute to win it” game, cards are placed between cups to stack them. The contestant then pulls the card out in hopes that

Luden [163]

Answer:

There is no friction between the card and the cup.

Explanation:

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2 years ago

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Part A: Explain why x = 5 makes 4x − 1 ≤ 19 true but not 4x − 1 < 19. (5 points) Part B: What value from the set {6, 7, 8, 9,

Elis [28]

Answer:

A: ≤ means less than OR equal to. < only means less than

B: 9

Explanation:

A: Because it would equal 19, and 19 is EQUAL than 19. 4(5) - 1 would equal 19, which is equal to 19, and not less than. ≤ means less than or equal to. < means less than. So its not true.

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2 years ago

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Vector has a direction and a magnitude, scalar only has a magnitude

Explanation:

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A car, traveling at , encounters a dip in the road. The radius of curvature at the bottom of the dip is . Each of the car’s four

labwork [276]

Answer:

spring deflection is x = (v2 / R + g) m / 4

Explanation:

We will solve this problem with Newton's second law. Let's analyze the situation the car goes down a road and finds a dip (hollow) that we will assume that it has a circular shape in the lower part has the car weight, elastic force and a centripetal acceleration

Let's write the equations on the Y axis of this description

Fe - W = m $a_{c}$

Where Fe is elastic force, W the weight and $a_{c}$ the centripetal acceleration. The elastic force equation is

Fe = - k x

4 (k x) - mg = m v² / R

The four is because there are four springs, R is theradio of dip

We can calculate the deflection (x) of the springs

x = (m v2 / R + mg) / 4

x = (v2 / R + g) m / 4

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3 years ago