Option (ii) B is the correct option. The object on the moon has greater mass.
To resolve this, utilize the formulas Force = Mass * Acceleration.
The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.
Calculating the mass on earth:
30 N = 9.8 m/s² * mass
This results in a mass of 3.0 kg for the object on Earth.
Calculating the mass of the moon:
30 N = 1.6 m/s²2 * mass
Thus, the moon's object has a mass of 19. kg.
This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).
To know more about Mass, refer to this link :
brainly.com/question/13386792
#SPJ9
Answer:
1-An object's velocity will change if a net force acts on the object. (True)
2-In order not to slow down, a car moving at a constant velocity needs a small net force applied. (False)
3- The net force which acts on an object which remains at rest is zero. (True)
4- If an object's speed does not change, no net force is acting on the object.(True)
5- If two objects are under the influence of equal forces, they have the same acceleration. (False)
6- During the collision of a car with a large truck, the truck exerts a greater force on the car than the car exerts on the truck.(False) (Newton Third Law)
The centripetal accelaration is increased by a factor of 4
<span>The Halogen outer layer is considered to be full with eight electrons. Halogen is also considered to be part of the Noble gases classification. The exchange of electrons in the halogen atom renders a photon energy pulse with produces light. The consentrated light spectrum is produced in the halogen light bulbs and halogen laser products.</span>
Mechanical energy (ME) is the sum of potential energy (PE) and kinetic energy (KE). When the toy falls, energy is converted from PE to KE, but by conservation of energy, ME (and therefore PE+KE) will remain the same.
Therefore, ME at 0.500 m is the same as ME at 0.830 m (the starting point). It's easier to calculate ME at the starting point because its just PE we need to worry about (but if we wanted to we could calculate the instantaneous PE and KE at 0.500 m too and add them to get the same answer).
At the start:
ME = PE = mgh
ME = 0.900 (9.8) (0.830)
ME = 7.32 J