This reaction forms triphenylmethanol from benzophenone. How could you use infrared spectroscopy to show that the benzophenone h
ad reacted (been consumed) and that the product of the reaction was triphenylmethanol
1 answer:
Complete Question
The complete question is shown on the first uploaded image
Answer:
The consumption of the reactant benzophenone and the production of triphenylmethanol can be detected using their IR absorption spectrum
This reaction is shown on the second uploaded image
The reactant benzophenone is a compound which contains a carbonyl functional group, and the stretching frequency of C=O bond has a high absorption at around and frequency band of this wavelength is absent in triphenylmethanol.
in the same vain the product triphenylmethanol is a compound which contains a hydroxyl (OH) functional group, and the stretching frequency of O-H bond has a high absorption at around and frequency band of this wavelength is absent in benzophenone.
To use infrared spectroscopy to show that the reaction is occurring is to show the disappearance of the frequency band which indictes the consumption of benzophenone and the appearance
frequency band which indictes the formation of triphenylmethanol
Explanation:
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The density of the metal object=6.0
Given:
Volume of the metal object=1.5ml
Mass of the metal object=9.0g
To find:
Density of the metal object
<u>Step by Step Explanation: </u>
Solution:
According to the formula, Density of the metal object can be calculated as
Where, m=mass of the metal object
=density of the metal object
v=volume of the metal object
We know the values of v=1.5ml and m=9.0g
Substitute these values in the above equation we get
=9.0/1.5
=6.0
Result:
Thus the density of the metal object is 6.0