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ella [17]
3 years ago
5

This reaction forms triphenylmethanol from benzophenone. How could you use infrared spectroscopy to show that the benzophenone h

ad reacted (been consumed) and that the product of the reaction was triphenylmethanol

Chemistry
1 answer:
nasty-shy [4]3 years ago
3 0

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The consumption of the reactant benzophenone and the production of  triphenylmethanol can be detected using their IR absorption spectrum

    This reaction is shown on the second uploaded image  

The reactant  benzophenone is a compound which contains a carbonyl functional group, and the stretching frequency of C=O bond has a high absorption at around 1680 \ cm^{-1} and frequency band of this wavelength is absent in triphenylmethanol.

in the same vain the product   triphenylmethanol is a compound which contains a hydroxyl (OH) functional group, and the stretching frequency of O-H bond has a high absorption at around 3474 \ cm^{-1} and frequency band of this wavelength is absent in benzophenone.

    To use infrared spectroscopy to show that the reaction is occurring is to show the disappearance of the 1680 \ cm^{-1}  frequency band which indictes the consumption of benzophenone and the appearance  3474 \ cm^{-1}  frequency band  which indictes the formation  of triphenylmethanol

Explanation:

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Explanation:

A solution is  prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume of 10.0 mL. Calculate the concentration of the dilute solution.

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Answer:

The answer to your question is pH = 6.3

Explanation:

Data

pH = ?

[H⁺] = 4.73 x 10⁻⁷ M

pH is the measure of the concentration of [H⁺]. pH measures the acidity of the solution. If the value of pH is between 0 and 6.9, the solution is an acid. If the pH is 7.0 the solution is neutral and if the pH is between 7.1 and 14, the solution is an alkali.

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