The mass in grams of NH₃ produced from the reaction is 3.4 g
<h3>Balanced equation</h3>
We'll begin by writing the balanced equation for the reaction. This illustrated below:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
<h3>How to determine the volume of NH₃ produced</h3>
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
Therefore,
2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃
<h3>How to determine the mass of NH₃ produced</h3>
We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:
22.4 dm³ = 1 mole NH₃
Therefore,
4.48 dm³ = 4.48 / 22.4
4.48 dm³ = 0.2 mole of NH₃
Finally, we shall determine the mass of NH₃ as follow:
- Molar mass of NH₃ = 17 g/mol
- Mole of NH₃ = 0.2 mole
- Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 0.2 × 17
Mass of NH₃ = 3.4 g
Learn more about stoichiometry:
brainly.com/question/13196642
#SPJ1
Hey there!:
Given [ OH⁻ ] = 9.00 x 10⁻⁴
We know that : [H⁺ ] [OH⁻ ] = 1 x 10⁻¹⁴
Thus [H⁺ ] = ( 1 x 10⁻¹⁴ ) / ( 9.00 x 10⁻⁴ )
[ H⁺ ] = 1 x 10⁻¹¹ M
therefore:
pH = - log [ H⁺ ]
pH = - log [ 1 x 10⁻¹¹ ]
pH = 10.95
Therfore pH = 10.95
I hope this will help !
Answer:
Is this on edgenuity or some type of virtual school Lmk and then i could help !
Explanation:
Answer:
C) Organic Weathering
Explanation:
Heat and Cold
And if some people start reporting and making fun of me in this answer don't listen to them.
They are hunting me down.