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lorasvet [3.4K]
3 years ago
15

A reddish layer of rust can form on old iron nails and bikes. In this chemical reaction, iron reacts slowly with oxygen in the a

ir. The chemical name for rust is iron oxide. What are the reactant(s) and product(s) of this reaction? Write down the equation, in words, for the formation of rust.
Chemistry
2 answers:
Molodets [167]3 years ago
5 0

Answer:

Iron slowly reacts with oxygen and forms rust. In this case, the reactants are iron and oxygen. The product is rust, or iron oxide. The chemical equation looks like this:

Explanation:

iron + oxygen → iron oxide

victus00 [196]3 years ago
4 0

Answer:

Iron slowly reacts with oxygen and forms rust. In this case, the reactants are iron and oxygen. The product is rust, or iron oxide. The chemical equation looks like this:

iron + oxygen → iron oxide

Explanation:

This was the answer straight from Plato. I hope that this helped you, please mark me the brainiest, like and rate my answer if it did! :)

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The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol
Ymorist [56]

Answer : The correct option is, (B) 0.11 M

Solution :

First we have to calculate the concentration PCl_3 and Cl_2.

\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}

\text{Concentration of }PCl_3=\frac{0.70moles}{1.0L}=0.70M

\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}

\text{Concentration of }Cl_2=\frac{0.70moles}{1.0L}=0.70M

The given equilibrium reaction is,

                            PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initially                 0.70        0.70              0

At equilibrium    (0.70-x)   (0.70-x)           x

The expression of K_c will be,

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

K_c=\frac{(x)}{(0.70-x)\times (0.70-x)}

Now put all the given values in the above expression, we get:

49=\frac{(x)}{(0.70-x)\times (0.70-x)}

By solving the term x, we get

x=0.59\text{ and }0.83

From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.

Thus, the concentration of PCl_3 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of Cl_2 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of PCl_5 at equilibrium = x = 0.59 M

Therefore, the concentration of PCl_3 at equilibrium is 0.11 M

3 0
3 years ago
What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?
Anna [14]

Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 2300 mm Hg = 3.02 atm  (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =0.0821Latm/Kmol

T =temperature = ?

T=\frac{PV}{nR}

T=\frac{3.02atm\times 15L}{0.0821Latm/K mol\times 0.6mol}=920K

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

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a lab is performed to do the study of pH and heat on the function of the catalase enzyme found in carrot plants. what would be c
ad-work [718]
It would be the ph and heat
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How to calculate precision chemistry.
chubhunter [2.5K]

Answer:

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Answer:

tri-

Explanation:

Examples could be Tri-angle, Tri-cycle, Tri-ceratops

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2 years ago
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