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Softa [21]
3 years ago
10

How many moles are there in 40g of calcium

Chemistry
1 answer:
drek231 [11]3 years ago
8 0
40 grams ÷ 40.08 grams/moles = 1 mole
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Esters are generally pleasant smelling compounds<br>True<br>False​
Rzqust [24]

Answer:

True

Explanation:

Esters are generally pleasantly smelling compounds. In fact, the fragrance industry uses esters to produce perfume, as well as uses esters as an ingredient to produce synthetic flavours and cosmetics, all of which have unique and pleasant smells.

8 0
3 years ago
Which of the followings are true 1,3-BPG? A. It regulates Hb B. It contains a high-energy bond C. It contains two ester bonds D.
weeeeeb [17]

Answer:

D. It contains a phosphate with higher phosphoryl transfer potential than ATP

Explanation:

1,3-Bisphosphoglycerate contains a phosphate group that has high phosphoryl transfer potential than ATP (they can transfer the phosphoryl group to ATP). Other high phosphoryl transfer potential groups include :Creatine kinase and phosphoenolpyruvate.

7 0
3 years ago
The volume occupied by a gas at STP is 250 L. At what pressure (in atm) will the gas occupy 1500 L, if the temperature is consta
Dennis_Churaev [7]

Answer:

6 atm

Explanation:

Using the formula P1V1=P2V2

P1= Initial Pressure

V1= Initial Volume

P2= Final Pressure

V2= Final Volume

And knowing that at stp gas will always be at 1 atm

250L(P2) = 1500

P2= 6 atm

8 0
2 years ago
What happens to the energy of gas particles when an elastic collision takes place?
julia-pushkina [17]
The answer is D because there is no forces of attraction or repulsion between gas particles .
3 0
2 years ago
Read 2 more answers
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

4 0
3 years ago
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