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meriva
3 years ago
8

Plz help, have a quiz on this plz PLZ

Chemistry
1 answer:
katovenus [111]3 years ago
7 0

Answer:

20.82

Explanation:

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Which is warmer -30C or -30 F?​
Burka [1]

-30°C is more warmer than -30°F...!

<h2>How??</h2>
  • Always Celsius is warmer than farheniet and also in coldness Celsius is colder than farheneit.
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The size of camphor kept in store house gradually decrease in size after few а days? ​
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Answer:

Because it goes through the process of sublimation.

Explanation:

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2 years ago
orbital cellulitis 5462 children included for study, 1347 (24%) were prescribed corticosteroids within 2 days of admission
son4ous [18]

It's unable to identify a decrease in LOS linked to corticosteroid exposure during hospitalization for ocular cellulitis in this database search. After two days of hospitalization, operational episodes and the prescription of corticosteroids were related to admission to the PICU.

Within two days of admission, 1347 (24%) of the 5462 children who were included in the research received a corticosteroid prescription. In analyses that controlled for age, the existence of meningitis, abscess, or visual problems, as well as the surgical episode and PICU admission within 2 days, corticosteroid prescription was not linked with LOS (e = 1.01, 95% confidence interval [CI]: 0.97-1.06). Among patients with a primary diagnosis of orbital cellulitis, corticosteroid exposure was linked to surgical events after two days of hospitalization (odds ratio = 2.05, 95% CI: 1.29-3.27) and 30-day readmission (odds ratio = 2.40, 95% CI: 1.52-3.78). Prospective, randomized control trials are required prior to the widespread usage of corticosteroids.

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4 0
2 years ago
How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?
Zolol [24]

Answer:

9.6 mol AgCl2

Explanation:

You have to use Avogadro's number: 6.023 x 10^23

5.78 x 10^24 molecules (1 mol AgCl2/ 6.023 x 10^23 molecules) =9.6 mol AgCl2

3 0
3 years ago
Calculate the molality of a 5.73 M ethanol (C2H5OH) solution whose density is 0.9327 g/mL.
Natalka [10]

Answer:

Molality = 8.57 m

Explanation:

Given data:

Molarity of solution = 5.73 M

density = 0.9327 g/mL

Molality of solution = ?

Solution:

Molality = moles of solute / kg of solvent.

Kg of solvent:

Mass of 1 L solution = density× volume

Mass of 1 L solution = 0.9327 g/mL × 1000 mL

Mass of 1 L solution = 932.7 g

Mass of solute:

Mass of 1 L = number of moles  × molar mass

Mass = 5.73 mol  × 46.068 g/mol

Mass = 263.97 g

Mass of solvent:

Mass of solvent = mass of solution - mass of solute

Mass of solvent = 932.7 g - 263.97 g

Mass of solvent = 668.73 g

In Kg = 668.73 /1000 = 0.6687 Kg

Molality:

Molality = number of moles of solute / mass of solvent in Kg

Molality = 5.73 mol /  0.6687 Kg

Molality = 8.57 m

4 0
3 years ago
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