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meriva
4 years ago
8

Plz help, have a quiz on this plz PLZ

Chemistry
1 answer:
katovenus [111]4 years ago
7 0

Answer:

20.82

Explanation:

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0.6 moles is the answer
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Citric acid is one component of some soft drinks. Suppose that 8 L of solution are made from 0.24 g of citric acid, C6H8O7. What
stealth61 [152]

Answer:

The correct answer is 0.15 × 10⁻³ M.

Explanation:

C₆H₈O₇ is the molecular formula of citric acid. The mass of the one mole of the substance that comprise Avogadro's no of molecules is termed as the molar mass of the substance.  

The molar mass of the citric acid (C₆H₈O₇) will be,  

6 × atomic mass of carbon + 8 × atomic mass of hydrogen + 7 × atomic mass of oxygen = 6×12 + 8×1 + 7×16 = 192. Thus, the molar mass of citric acid is 192 g/mol.  

The value of the solution given in the question is 8 L.  

The mass of citric acid given is 0.24 g or 240 mg, which can also be written as 240/1000 g or 240 × 10⁻³ g.  

The number of moles can be calculated by using the formula = mass / molar mass. Thus, by putting the values we get,  

= 240 × 10⁻³ g / 192 g/mol

= 1.25 × 10⁻³ mol

The number of moles of the solute present in the 1 liter of the solution is termed as the molarity of the solution. The formula of molarity or M is,  

= no of moles of solute / volume of solution in L

Now putting the values we get,  

= 1.25 × 10⁻³ mol / 8 L

= 0.156 × 10⁻³ M

Hence, the molarity of citric acid in the given solution is 0.15 × 10⁻³ M

4 0
4 years ago
Rank the compounds by the ease with which they ionize under sn1 conditions. rank the compounds from easiest to hardest. to rank
marysya [2.9K]
The rate of Formation of Carbocation mainly depends on two factors'

                    1)  Stability of Carbocation:
                                                              The ease of formation of Carbocation mainly depends upon the ionization of substrate. If the forming carbocation id tertiary then it is more stable and hence readily formed as compared to secondary and primary.

                     2) Ease of detaching of Leaving Group:
                                                                                   The more readily and easily the leaving group leaves the more readily the carbocation is formed and vice versa. In given scenario the carbocation formed is tertiary in all three cases, the difference comes in the leaving group. So, among these three substrates the one containing Iodo group will easily dissociate to form tertiary carbocation because due to its large size Iodine easily leaves the substrate, secondly Chlorine is a good leaving group compared to Fluoride. Hence the order of rate of formation of carbocation is,

                                            R-I > R-Cl > R-F

                                               B   >  C  >  A

3 0
3 years ago
4.) Calculate the density of carbon monoxide if 22.4 L of
KATRIN_1 [288]

Answer: Density (ρ) = 1.25 gram/liter

Explanation:

p=\frac{m}{v}

=\frac{28.0}{22.4}

= 1.25 gram/liter

4 0
3 years ago
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