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Vika [28.1K]
3 years ago
10

What is used to measure the distance of nearby stars??

Chemistry
1 answer:
Allisa [31]3 years ago
6 0
Light years? if you are talking about the distance to the star.
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During oxidation what happen
Agata [3.3K]
Oxidation is when a substance gains oxygen molecules. For example when hydrogen reacts with oxygen it forms H₂O. The H₂ has been oxidised.
4 0
3 years ago
How to calculate density (what’s the formula) <br> density=_ divided by _
Sphinxa [80]

Answer:

density equals weigt divided by volume

Explanation:

density =  \frac{m}{v}

8 0
3 years ago
The electron dot structure for CI is
finlep [7]
The correct option is C.
A Lewis dot diagram is a representation of the valence electron of  an atom, which uses dot around the symbol of the atom. Chlorine has seven electrons in its outermost shell, these seven electrons are arranged in form of dot around the atom of chlorine. If you count the number of dot given in option C, you will notice that they are seven.
6 0
3 years ago
Read 2 more answers
Question 6
I am Lyosha [343]

Answer:

A. is the correct point.

Explanation:

This is true because no matter how many mL of water is added, the solution only gets more height; the concentration in everything else stays the same, and water doesn't have any concentration. Very confusing, I know. Good luck!

4 0
3 years ago
S(s)+3F2(g)-&gt;SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?
Brilliant_brown [7]

Answer:  There are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)

Here, 1 mole of S is reaction with 3 moles of F_{2} which means 1 mole of S requires 3 moles of F_{2}.

Therefore, moles of F_{2} required to react completely with 2.30 moles S are calculated as follows.

1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}

Thus, we can conclude that there are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

3 0
3 years ago
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