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Ray Of Light [21]
2 years ago
5

How do you revive a person

Chemistry
2 answers:
telo118 [61]2 years ago
8 0

Answer:

By revive, I assume you're talking about medical assistance.

Explanation:

You can use CPR, where you lay a person back, hold their head up, and push on their chest to the beat "staying alive", in which it keeps their heart beating. If they aren't breathing, you can do mouth to mouth breathing, and continue the process until help arrives or.. the person is no longer with us.

If you have a defibrillator, you can use it on a low amp, or whatever amp you think would be most suitable for the condition of the person.

*yes the person below copy/pasted my thingy. yes its funny.

Mariana [72]2 years ago
5 0

Answer: i don't  even know what you said but i think you said this,

CPR, where you lay a person back, hold their head up, and push on their chest to the beat "staying alive", in which it keeps their heart beating. If they aren't breathing, you can do mouth to mouth breathing, and continue the process until help arrives or.. the person is no longer with us,

If you have a defibrillator, you can use it on a low amp, or whatever amp you think would be most suitable for the condition of the person.

Hope this helps :)

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Which of the temperatures below is most likely to be the boiling point of water at 880 torr?view available hint(s)which of the t
Luden [163]
Boiling point<span>  is the </span>temperature<span> at which the vapor pressure of the liquid equals the surrounding pressure.

Above boiling point point, liquid get converted into vapour.

Now, boiling point of water is 100 oC at room pressure. Room pressure is equal to 760 torr. Thus, at 100 oC, vapour pressure of water becomes equal to 760 torr.

Now, if external pressure is increased to 880 torr, more heat is to be supplied so that vapour pressure of water equals 880 torr.

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6 0
3 years ago
How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide
Marat540 [252]

Answer:

\boxed{\text{2.00 mol}}

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r:      58.32

          Mg(OH)₂ + … ⟶ … + 2HOH

m/g:       58.3

(a) Moles of Mg(OH)₂

\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}

The reaction will form \boxed{\textbf{2.00 mol}} of water.

6 0
3 years ago
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