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2 years ago

How do you revive a person

Chemistry

2 answers:

telo118 [61]2 years ago

8 0

Answer:

By revive, I assume you're talking about medical assistance.

Explanation:

You can use CPR, where you lay a person back, hold their head up, and push on their chest to the beat "staying alive", in which it keeps their heart beating. If they aren't breathing, you can do mouth to mouth breathing, and continue the process until help arrives or.. the person is no longer with us.

If you have a defibrillator, you can use it on a low amp, or whatever amp you think would be most suitable for the condition of the person.

*yes the person below copy/pasted my thingy. yes its funny.

Mariana [72]2 years ago

5 0

Answer: i don't even know what you said but i think you said this,

CPR, where you lay a person back, hold their head up, and push on their chest to the beat "staying alive", in which it keeps their heart beating. If they aren't breathing, you can do mouth to mouth breathing, and continue the process until help arrives or.. the person is no longer with us,

If you have a defibrillator, you can use it on a low amp, or whatever amp you think would be most suitable for the condition of the person.

Hope this helps :)

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What is the mass, in pounds, of 389 mL of a gas that has a density of 1.29 g/L?

devlian [24]

Answer: Mass of gas is 0.001 pounds.

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of gas = ?

Density of gas = $1.29g/L$

Volume of gas = 389 ml = 0.389 L (1L=1000ml)

Putting in the values we get:

$1.29g/L=\frac{mass}{0.389L}$

$mass=0.5grams$

$mass=0.5\times 0.002lb=0.001lb$ (1g =0.002 lb)

Thus the mass of gas is 0.001 pounds.

7 0

3 years ago

What is the name of the group 8 elements and what makes them special?

Illusion [34]

Iron, Ruthenium, Osmium, and Hassium.

They're transition metals

8 0

3 years ago

Which best describes the relationship between the terms frequency, wavelength, and hertz?

Oksanka [162]

Answer:

The correct answer is - Frequency is the number of wavelengths, which is measured in hertz.

Explanation:

Frequency is the number of waves that go through a fixed point at a particular time. Hertz is the SI unit for frequency which means that one hertz is equal to a unit number of waver passes in a unit time to a fixed point.

As the frequency of a wave increases which means the number of waves increases in the unit time, the shorter the wavelength will be.

a higher frequency wave has more energy than a lower frequency wave with the same amplitude.

5 0

3 years ago

For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?

damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

The moles of CH3COO- are its initial moles - the moles of HCl added

And moles of CH3COOH are its initial moles + moles HCl added

Moles CH3COO-:

Initial moles = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

pH = 3.90

<h3>The pH of the buffer is 3.90</h3>

3 0

3 years ago

A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.

GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂ + I₂ ⇄ 2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

H₂ + I₂ ⇄ 2HI

In: 0.001 0.002 -

R: x x 2x

Eq: 0.001-x 0.002-x 0.00187

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵ moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is = (HI)² / (H₂) . (I₂)

0.00187 ² / 6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0

3 years ago