In which of the following situations are there a force on the object balanced

12. Which of the following statements about

aliya0001 [1]

A seems to be correct

8 0

2 years ago

In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu

Mamont248 [21]

We'll look at two properties:

1. The variation in temperature

2. The material's heat transfer coefficient

By taking an example;

Use a circular rod made of a certain material (for example, steel) that is insulated all the way around.

One end of the rod is immersed in a huge reservoir of 100°C water, while the other is immersed in water at 40°C. The cold water is kept in an insulated cylinder on both sides. The temp of the chilly water is measured using a meter as a time - dependent.

Conclusion of experiment;

Heat is transferred from a hot location to a cooler region.
Whenever heat is applied to a body, its thermal power rises, and its temperature rises.

Learn more:

brainly.com/question/21532922?referrer=searchResults

4 0

2 years ago

The diameter of an atom is 1.1×10−10m and the diameter of its nucleus is 1.0×10−14m. Part A What percent of the atom's volume is

77julia77 [94]

To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,

$\% Percent = \frac{V_{nucleus}}{V_{atom}}*100$

$\% Percent = \frac{4/3 \pi (d_{nucleus}/2)^3}{4/3 \pi (d_{atom}/2)^3}*100$

$\% Percent = \frac{(d_{nucleus}/2)^3}{ (d_{atom}/2)^3}*100$

$\% Percent =\frac{(1.0*10^{-14}/2)^3}{ (1.1*10^{-10}/2)^3}*100$

$\% Percent = 7.51*10^{-13}*100$

$\% Percent = 7.51*10^{-11}\%$

Therefore the percent of the atom's volume is occupied by mass is $7.51*10^{-11}\%$

3 0

2 years ago

Let's say you go on a run and start to sweat because you are heating up.

Jobisdone [24]

Answer:

kinetic to thermal

Explanation:

4 0

3 years ago

During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 4.02 s, how high above the point where i

alukav5142 [94]

Answer:

d = 19.796m

Explanation:

Since the ball is in the air for 4.02 seconds, the ball should reach the maximum point from the ground in half the total time, therefore, t=2.01s to reach maximum height. At the maximum height, the velocity in the y-direction is 0.

So we know t=2.01, vi=0, g=a=9.8m/s and we are solving for d.

Next, you look for a kinematic equation that has these parameters and the one you should choose is:

$d=vt+\frac{1}{2}at^2$

Now by substituting values in, we get

$d=(0\frac{m}{s})*(2.01s)+\frac{1}{2}(9.8\frac{m}{s^2})(2.01)^2$

d = 19.796m

7 0

3 years ago