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3 years ago

If 4.35 KJ of

1 answer:

4 0

4.186 Joules equals 1 cal.
1 cal is the amount of energy needed to increase in 1ºC the temperature of 1 gram of water. If we add to 15.5 grams of water 4350 Joules, we are adding approximately 1039.2 cal. (4350÷4.186≈1039.2)
This energy though is being divided by all the gram in the water. 1039.2cal÷15.5g≈67.0cal/g
4.35kJ would increase the water's temperature in approximately 67ºC, putting it at 72ºC. The state would remain the same - liquid - though much closer to boil.

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3 years ago

What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin

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Answer: The total volume of the gaseous products is 1044.29 L

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22.4 L of volume is occupied by 1 mole of a gas

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$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

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2 moles of butane produces 8 moles of carbon dioxide

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3 years ago

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C. Melting ice.
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3 years ago