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Oliga [24]
3 years ago
6

If 4.35 KJ of

Chemistry
1 answer:
joja [24]3 years ago
4 0
4.186 Joules equals 1 cal.
1 cal is the amount of energy needed to increase in 1ºC the temperature of 1 gram of water. If we add to 15.5 grams of water 4350 Joules, we are adding approximately 1039.2 cal. (4350÷4.186≈1039.2)
This energy though is being divided by all the gram in the water. 1039.2cal÷15.5g≈67.0cal/g
4.35kJ would increase the water's temperature in approximately 67ºC, putting it at 72ºC. The state would remain the same - liquid - though much closer to boil.
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A sample of ideal gas is in a sealed container. The pressure of the gas is 485 torr , and the temperature is 40 ∘C . If the temp
Fantom [35]

Answer:

537.68 torr.

Explanation:

  • We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and V are constant, and have different values of P and T:

<em>(P₁T₂) = (P₂T₁).</em>

P₁ = 485 torr, T₁ = 40°C + 273 = 313 K,

P₂ = ??? torr, ​T₂ = 74°C + 273 = 347 K.

∴ P₂ = (P₁T₂)/(P₁) = (485 torr)(347 K)/(313 K) = 537.68 torr.

3 0
3 years ago
What is the ph value of the produced solution when hcl reacts with naoh ?
algol13

Answer:

The answer to your question is: 7

Explanation:

The reaction between HCl and NaOH is a neutralization reaction, that means that the products will be water and a salt and the pH will be 7.

                     HCl + NaOH  ⇒  NaCl + H₂O

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