I assume you mean:
[x^(5/6)]/[x^(1/6)]
The rule for dividing similar bases with different exponents is:
(a^b)/(a^c)=a^(b-c)
In this case we have:
x^(5/6-1/6)
x^(4/6)
x^(2/3)
Answer:
x = 12
Step-by-step explanation:
Solve for x:
360 - 30 x = 0
Subtract 360 from both sides:
(360 - 360) - 30 x = -360
360 - 360 = 0:
-30 x = -360
Divide both sides of -30 x = -360 by -30:
(-30 x)/(-30) = (-360)/(-30)
(-30)/(-30) = 1:
x = (-360)/(-30)
The gcd of 360 and -30 is 30, so (-360)/(-30) = (-(30×12))/(30 (-1)) = 30/30×(-12)/(-1) = (-12)/(-1):
x = (-12)/(-1)
(-12)/(-1) = (-1)/(-1)×12 = 12:
Answer: x = 12
Answer:
The volume of the solid is the volume of the prism minus the volume of the cylinder.
For the cylinder, diameter = d = 4 cm
radius = d/2 = (4 cm)/2 = 2 cm
V = volume of prism - volume of cylinder
The volume of a prism is length times width times height.
The volume of a cylinder is pi times the square of the radius times the height.
V = LWH - (pi)r^2h
V = 6 cm * 6 cm * 15 cm - (pi)(2 cm)^2(15 cm)
V = 540 cm^3 - 60pi cm^3
V = (540 - 60pi) cm^3
Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if 
here;
Thus;
∴
Hence, we can conclude that r(t) and s(t) are parallel.
Answer:
you have to start with you b which in your problem is 5 so put a point at 5 on the y-axis on your graph. then with the M (the fraction numbers) you have to move either up or down depending if there is a negative number. so yours is 1/2 so then you would start at the 5 point and go up 1 and right 2 then you just keep repeating till you get a few points and can make a line then you just do the same thing for the other equation. start at 3 on the y-axis and then go up 3 and right 4 then just keep repeating till you get a few point and can create a line at the end the lines should cross each other like perpendicular lines
Step-by-step explanation:
hope this helps:)
