Answer:
d = 5/6t
Step-by-step explanation:
5 stories every 6 seconds
at 12 seconds, it would have travelled 10 seconds.
using this 2 data in this formula
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
Note : d = y, t = x;
d1 = 5, t1 = 6, d2 = 10, t2 = 12
we have
(d - 5)/(t-6) = (10-5)/(12-6)
(d - 5)/(t-6) = 5/6
d = 5/6(t-6) + 5
d = 5/6t -5+5
d = 5/6t
Answer
given,
on first stop
number of car = 20 and number of trucks = 18
on second stop
number of car = 18 and number of trucks = 10
we need to calculate which rest stop has higher ratio of car to truck.
Rest Stop 1
ratio= r₁ =
r₁ =
r₁ =
Rest Stop 2
ratio= r₂ =
r₂ =
r₂=
hence, r₂ > r₁
rest stop 2 has more car to truck ratio than rest stop 1
Answer: He rides for 2.5 hours or 2 and a half hours.
Step-by-step explanation:
He needs to complete a trajectory of 22.5 kilometers.
He rides 9 kilometers per hour.
Divide the total by the amount of kilometers that he rides.
Answer:
We fail to reject H0; Hence, we conclude that there is no significant evidence that the mean amount of water per gallon is different from 1.0 gallon
Pvalue = - 2
(0.98626 ; 1.00174)
Since, 1.0 exist within the confidence interval, then we can conclude that mean amount of water per gallon is 1.0 gallon.
Step-by-step explanation:
H0 : μ= 1
H1 : μ < 1
The test statistic :
(xbar - μ) / (s / sqrt(n))
(0.994 - 1) / (0.03/sqrt(100))
-0.006 / 0.003
= - 2
The Pvalue :
Pvalue form Test statistic :
P(Z < - 2) = 0.02275
At α = 0.01
Pvalue > 0.01 ; Hence, we fail to reject H0.
The confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 99% confidence level = 2.58
Margin of Error = 2.58 * 0.03/sqrt(100) = 0.00774
Confidence interval :
0.994 ± 0.00774
Lower boundary = (0.994 - 0.00774) = 0.98626
Upper boundary = (0.994 + 0.00774) = 1.00174
(0.98626 ; 1.00174)
V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
