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almond37 [142]
3 years ago
15

YALL HELP ME IM DESPERATE AND NEED AN A ON THIS!

Chemistry
1 answer:
Sidana [21]3 years ago
6 0
Hey there!

Your question states: <span>You dissolve 0.005 mol of potassium chloride (KCI) in0.50 L of water. What is the molarity of the solution? So, basically in this question here, this would be just like converting the cup's to gallons. It would be the </span>exact same thing.

The, when doing this problem, we would do the following . . . 

\left \{\boxed{\boxed{0.005}} \ divided \ by \ \boxed{\boxed{0.50}} \  { \atop {}} \right.\}

and \ from  \ doing \ this, \ we \ get \ for \ your \ and . . .

\boxed{\boxed{ .01m}}

Hope this helps.
~Jurgen
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What are the chemical symbols of the particles found in the calcium chloride crystal (lattice)​
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Answer:

Formula and structure: The chemical formula of calcium chloride is CaCl2, and its molar mass is 110.983 g/mol. It is an ionic compound consisting of the calcium cation (Ca2+) and two chlorine anions (Cl-). The bivalent calcium metal forms an ionic bond with two chlorine atoms, as shown below.

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For each molecule of glucose processed during glycolysis, the net yield is ____. 1. two molecules of NADH, two of ATP, and two o
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Answer: 1. two molecules of NADH, two of ATP, and two of pyruvate

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A 312 g sample of a metal is heated to 257.128 °C and plunged into 200 g of water at a temperature of 41.933 °C. The final tempe
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<h3>Answer:</h3>

0.362 J/g °C

<h3>Explanation:</h3>

We are given:

Mass of metal = 312 g

Initial temperature of the metal = 257.128 °C

Mass of water = 200 g

Initial temperature = 41.933 °C

Final temperature of water = 67.555 °C

Specific heat capacity of water = 4.184 J/g °C

We are required to calculate the specific heat capacity of the metal;

Step 1: Heat gained by water

Quantity of heat = mass × specific heat × change in temperature

Q=m × c × Δt

Change in temperature, Δt = 25.622 °C

Therefore,

Heat gained by water = 200 g × 4.184 J/g °C × 25.622 °C

                                    = 21,440.49 Joules

<h3>Step 2: Heat released by the metal </h3>

Change in temperature of the metal, Δt =(257.128 °C-67.555 °C)

                                                                 = 189.573 °C

Q = mcΔt

Assuming the specific heat capacity of the metal is c

Q= 312 g × 189.573 °C × c

 = 59,146.776c Joules

<h3>Step 3: Calculate the specific heat capacity of the metal</h3>

The heat released by the metal is equivalent to heat gained by water.

Therefore;

59,146.776c J = 21,440.49 J

 c = 21,440.49 J ÷  59,146.776

    = 0.362 J/g °C

Thus, the specific heat capacity of the metal is 0.362 J/g °C

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3 years ago
Water, in its liquid form, is one of the most
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Answer:

Is A

Explanation:

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