Molarity (M) = moles of the solute (mol) / Volume of the solution (L)
The molarity of the given KCl solution = 2.10 M
Volume of the given KCl solution = 85.0 mL
Hence,
2.10 M = Moles of KCl / 85.0 x 10⁻³ L
Moles of KCl = 2.10 M x 85.0 x 10⁻³ L
= 0.1785 mol
Moles (mol) = Mass (g) / Molar mass (g mol⁻¹)
Molar mass of KCl = 74.56 g mol⁻¹
Hence,
0.1785 mol = Mass of KCl / 74.56 g mol⁻¹
Mass of KCl = 0.1785 mol x 74.56 g mol⁻¹
= 13.30 g
Hence, mass of given KCl in 85.0 mL is 13.30 g.
Answer:
c
Explanation:
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The molar solubility is 7.4×
M and the solubility is 7.4× g/L .
Calculation ,
The dissociation of silver bromide is given as ,
→ 
+ 
S
- S S
Ksp = [ ] [ ] = [S] [ S ] = 
S = √ Ksp = √ 5. 5×
= 7.4×
The solubility =7.4× g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of is dissociates and form one mole of each and ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4× mol/L = 7.4× M
To learn more about molar solubility ,
brainly.com/question/16243859
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Zinc (ii) sulfate heptahydrate has a formula of ZnSO4.7H2O
Therefore, note that one mole of ZnSO4.7H2O, contains 7 moles of H2O,
Hence, 3.8 moles of ZnSO4.7H2O will contain;
3.8 × 7/1
= 26.6 moles of H2O
