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2 years ago

14

HELP ME PLEASE! according ohm's law if the resistance remains constant what would happen if you decrease the amount of voltage b

y 1/2
there would be no change in the current

the amount of current would be decrease 1/2

the amount of current would double

1 answer:

SpyIntel [72]2 years ago

7 0

B.
technically it would depend if the resistors were in series or parallel but B is the answer.

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Final velocity (v) = 0 m/s

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Now, change in momentum is given as:

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$J=f\times \Delta t$

Rewriting the above equation in terms of 'f', we get:

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Plug in the given values and solve for 'f'. This gives,

$f=\frac{-76.00\ Ns}{7.00\ s}\\\\f=-10.86\ N$

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