We know from gas equation:
PV=mRT
Where:
P is pressure
V is the volume of the balloon
m is the mass of gas in the balloon (constant)
R is universal gas constant divided by mean molar wt of air (about 28 g/mol) T is thermodynamic temperature (T in Kelvin; T=273 + t (in deg C)
P1 * V1 =m*R*T1 ---- (i) P2 * V2 =m*R*T2 ---- (ii)
Dividing 1 by 2 we get:
V1 / V2 = (P2/P1) * (T1/T2)
Given:V1=27.6, P1=736mmhg, T1 = 273+26.1=299.1V2=?, P2 = 360mmhg, T2 = 273+(-14)=259
so, V2 = 27.6*(736/360)*(259/299.1) = 48.86
Answer:
Option A is correct.
Explanation:
The force of gravity does not affect the horizontal component in projectile motion; a projectile maintains a constant horizontal velocity. So there is no acceleration ( a=0 ) in horizontal direction as velocity remains constant.
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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
Answer:
1,700feet
Explanation:
If an object in free fall travels a distance s that is directly proportional to the square of the time t, this can be represented mathematically as;
S = kt²where;
k is the proportionality constant
K = s/t²
s1/t1²= s2/t2²= Sn/tn²= k for values of the distance and time. Using the formula
s1/t1² = s2/t2² where;
s1 is the falling distance in time t1 s2 is the falling distance in time t2
Given s1 = 1088feet, t1 = 8secs, s2 = ? t2 = 10secs
Substituting this value in the formula to get s2, we have;
1088/8²= s2/10²
64s2= 108800
s2 = 108800/64
s2 = 1,700feet
This means the object will fall a distance of 1,700feet in 10seconds
